Find value for x please and thank you
1 answer:
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Answer:
Step-by-step explanation:
Consider the selling of the units positive earning and the purchasing of the units negative earning.
<h3>Case-1:</h3>- Mr. A purchases 4 units of Z and sells 3 units of X and 5 units of Y
- Mr.A earns Rs6000
So, the equation would be
- Mr. B purchases 3 units of Y and sells 2 units of X and 1 units of Z
- Mr B neither lose nor gain meaning he has made 0₹
hence,
- Mr. C purchases 1 units of X and sells 4 units of Y and 6 units of Z
- Mr.C earns 13000₹
therefore,
Thus our system of equations is
<u>Solving </u><u>the </u><u>system </u><u>of </u><u>equations</u><u>:</u>
we will consider elimination method to solve the system of equations. To do so ,separate the equation in two parts which yields:
Now solve the equation accordingly:
Solving the equation for x and y yields:
plug in the value of x and y into 2x - 3y + z = 0 and simplify to get z. hence,
Therefore,the prices of commodities X,Y,Z are respectively approximately 1477, 1464, 1437
we are given
system of equations
First equation is
Second equation is
now, we can find augmented matrix
now, we can change it into reduced row echelon form
step-1: multiply the 1st row by 1/3
step-2:add -3 times the 1st row to the 2nd row
step-3:multiply the 2nd row by 1/4
step-4: add 2/3 times the 2nd row to the 1st row
so, we get
Answer is (5,-8)
Refer to the attached diagram for help.
All radii of a circle are congruent.
Tangent segs LP and LQ are congruent. (Tangent segs drawn to a circle from the same point are congruent)
Because of this we can establish OPLQ as a kite.
OPLQ is a kite implies that OL bis. angle PLQ.
An angle bis. divides an angle into 2 congruent, parts, so angle OLP must be 30 degrees.
Since tangents form right angles with the radius, angle OPL is right.
Now we have a right triangle OPL with a 30-degree angle. The other angle must be 60 degrees because of the no-choice theorem. (180-(30+90)) = 60
We know that OP is 6 because it is a radius of circle O. How do we use that to find OL? Well, we <em>could</em> use trig, but you might recognize this as a special triangle!
The side opposite the 30 degree angle = x
The side opposite the right angle = 2x
So OL must be 12!
All radii of a circle are congruent.
Tangent segs LP and LQ are congruent. (Tangent segs drawn to a circle from the same point are congruent)
Because of this we can establish OPLQ as a kite.
OPLQ is a kite implies that OL bis. angle PLQ.
An angle bis. divides an angle into 2 congruent, parts, so angle OLP must be 30 degrees.
Since tangents form right angles with the radius, angle OPL is right.
Now we have a right triangle OPL with a 30-degree angle. The other angle must be 60 degrees because of the no-choice theorem. (180-(30+90)) = 60
We know that OP is 6 because it is a radius of circle O. How do we use that to find OL? Well, we <em>could</em> use trig, but you might recognize this as a special triangle!
The side opposite the 30 degree angle = x
The side opposite the right angle = 2x
So OL must be 12!
Answer:
The answer to your question is height = 12 mm
Step-by-step explanation:
Data
l = w = 9 mm
V = 324 mm³
h = ?
Formula
V =
Solve for h
3V = Ab h
3V / Ab = h or h = 3V / Ab
Find the area of the base
Ab = l x w
= 9 x 9
= 81 mm²
Substitution
h =
Simplification
h =
Result
h = 12 mm