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2 years ago

URGENT!!!!!!!!! will give 30 points and brainlist and if its right i might pay 20$$$$ dollars no cap!!!

Mathematics

1 answer:

7nadin3 [17]2 years ago

7 0

Hey buddy so basically you have to find the unknown sides length and it leads to the escape so here’s the outcome:
A>F>C>H>ESCAPE
Hope this helps also I don’t need the 20$ dollars :)

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The ratio of dogs to cats being treated at a veterinarian's office this week is 5 : 2. Suppose there are 168 dogs and cats sched

Alexeev081 [22]

Answer:

48 cats

Step-by-step explanation:

Am interesting factoid about ratios:

The ratio $a:b$ can be separated into fractional parts of $\frac{a}{a + b}$ and $\frac{b}{a + b}$ . We need to know the cat part. $\frac{2}{5 + 2} = \frac{2}{7}$ , so that is the fraction part. Then, we multiply this fraction by 168 to get the total number of cats. This number is 48.

4 0

2 years ago

How many gallons of paint will you need in order to paint a wall that is 42 feet wide and 27 feet high if one gallon will cover

GREYUIT [131]

Answer:

42 x27 //// 1134 is the area

Step-by-step explanation:

1134/ 200= 5.67

You have to round up because you can’t get .67 of a paint bucket So you would have to round it out. About 6 buckets.

6 0

2 years ago

Simplify by performing long division.

olga_2 [115]

Answer:

the answer is A. 3x-2+2/x+1

3 0

2 years ago

Evaluate 12 x (4^-2/4^-4) A 1/4 B 3/4 C 16 D 192

MrMuchimi

12 ×4^4/4^2
=12×4^2
=12×16
=192

7 0

3 years ago

Find sinϴ and cosϴ if tanϴ=1/4 and sinϴ>0

eduard

If you're using the app, try seeing this answer through your browser: brainly.com/question/2787701

_______________

$\mathsf{tan\,\theta=\dfrac{1}{4}\qquad\qquad(sin\,\theta\ \textgreater \ 0)}\\\\\\
\mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{1}{4}}\\\\\\
\mathsf{4\,sin\,\theta=cos\,\theta\qquad\quad(i)}$

Square both sides:

$\mathsf{(4\,sin\,\theta)^2=(cos\,\theta)^2}\\\\
\mathsf{4^2\,sin^2\,\theta=cos^2\,\theta}\\\\
\mathsf{16\,sin^2\,\theta=cos^2\,\theta\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{16\,sin^2\,\theta=1-sin^2\,\theta}$

$\mathsf{16\,sin^2\,\theta+sin^2\,\theta=1}\\\\
\mathsf{17\,sin^2\,\theta=1}\\\\
\mathsf{sin^2\,\theta=\dfrac{1}{17}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{1}{17}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{1}{\sqrt{17}}}$

Since $\mathsf{sin\,\theta}$ is positive, you can discard the negative sign. So,

$\mathsf{sin\,\theta=\dfrac{1}{\sqrt{17}}\qquad\quad\checkmark}$

Substitute this value back into $\mathsf{(i)}$ to find $\mathsf{cos\,\theta:}$

$\mathsf{4\cdot \dfrac{1}{\sqrt{17}}=cos\,\theta}\\\\\\
\mathsf{cos\,\theta=\dfrac{4}{\sqrt{17}}\qquad\quad\checkmark}$

I hope this helps. =)

Tags: trigonometric identity relation trig sine cosine tangent sin cos tan trigonometry precalculus

7 0

2 years ago