Answer:
You can simplify the problem down by recognizing that you just need to keep track of the integers you've seen in array that your given. You also need to account for edge cases for when the array is empty or the value you get would be greater than your max allowed value. Finally, you need to ensure O(n) complexity, you can't keep looping for every value you come across. This is where the boolean array comes in handy. See below -
public static int solution(int[] A)
{
int min = 1;
int max = 100000;
boolean[] vals = new boolean[max+1];
if(A.length == 0)
return min;
//mark the vals array with the integers we have seen in the A[]
for(int i = 0; i < A.length; i++)
{
if(A[i] < max + 1)
vals[A[i]] = true;
}
//start at our min val and loop until we come across a value we have not seen in A[]
for (int i = 1; i < max; i++)
{
if(vals[i] && min == i)
min++;
else if(!vals[i])
break;
}
if(min > max)
return max;
return min;
}
Depending on the data all answers can be used to make it easier to read. Without more info I would go with Borders (D) since they are the best way to group the data when printed, especially if the print is in color.
Alignment would be the correct answer only if the data goes out of cell boundaries. Font Color usually makes it harder to read because of bad contrast and finally changing the Font Style has a minimal effect since the default one is already pretty readable.
I believe the answer is B. False.
Hope this helps! ^^
Answer:
There are two ways to find the average of a list of numbers in Python. You can divide the sum() by the len() of a list of numbers to find the average. Or, you can find the average of a list using the Python mean() function
Explanation: