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2 years ago

10 and 25

Mathematics

2 answers:

LekaFEV [45]2 years ago

8 0

Answer:

LCM of 10 and 25 is 50

2 common multiples is 50 and 100

Bess [88]2 years ago

7 0

Answer:

https://www.khanacademy.org/math/cc-sixth-grade-math/cc-6th-factors-and-multiples/cc-6th-lcm/v/least-common-multiple-exercise

you can wacth here

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Can you please help me solve this?

oee [108]

So, i would use the add the two equation method, so add those to get:
2e=-4
e=-2
then plug in e to get d, so d+-2=1
d=3
plug into the other one to make sure
-3+-2=-5
so it would be (3,-2)

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3 years ago

What word best fits this definition

postnew [5]

Answer:

EXTRAPOLATION.

Step-by-step explanation:

We have been given a crossword puzzle in the figure

And we need to fill the missing word in this which has to be a mathematics word because we need to follow the pattern

And all words are mathematical

Hence, The word that can be filled there is EXTRAPOLATION.

Extrapolation means in mathematics is finding value of the variable on basis of the relationship this variable have with other variable.

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3 years ago

True or false: given a sample mean of 2.1 and a sample standard deviation of 0.7 from a sample of 10 data points, a 90% confiden

iris [78.8K]

Your answer is false.

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3 years ago

Micah is watching a TV program that is 2 hours long during the program there are six commercials that are each 90 sec. How many

Sergeu [11.5K]

Answer:

111 minutes

Step-by-step explanation:

step 1

Find out how long are the six commercial

Multiply the number of commercials by 90 seconds

$90(6)=540\ sec$

Convert to minutes

Remember that

$1\ min=60\ sec$

$540\ sec=540/60=9\ min$

step 2

Subtract the duration of six commercials from the duration of the program

Remember that

$1\ h=60\ min$

$2\ h=2(60)=120\ min$

therefore

$120-9=111\ min$

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3 years ago

Verify the trigonometric identity. convert the left side of the relationship to look like the right side.

Tomtit [17]

Answer:

Verified

Step-by-step explanation:

Use $\tan{x}=\frac{\sin{x}}{\cos{x}}$ , $\sin^2{x}+\cos^2{x}=1$ and $\sec{x}=\frac{1}{\cos{x}}$

LHS= $\tan^2{x}+1=\frac{\sin^2{x}}{\cos^2{x}} + 1=\frac{\sin^2{x}+\cos^2{x}}{\cos^2{x}}=\frac{1}{\cos^2{x}}=\sec^2{x}$ =RHS

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2 years ago