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3 years ago

The fraction 5/8 is located between what two fractions?

Mathematics

2 answers:

S_A_V [24]3 years ago

8 0

C is the answer I pretty sure of it

Digiron [165]3 years ago

4 0

4/10 = 16/40
5/8 = 25/40
2/5 = 16/40

1/2 = 12/24
5/8 = 15/24
2/3 = 16/24

3/7 = 48/112
5/8 = 70/112
10/16 = 70/112

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Solve for x. Enter the solutions from least to greatest. (x−1)^2−9=0

Leno4ka [110]

Step-by-step explanation:

(x−1)²−9=0

(x-1)²= 9

x-1 = ±√9

x-1 = ±3

x = 1-3=-2 or x=1+3=4

the solution = {-2,4}

6 0

3 years ago

Find the area of the triangle ABC with the coordinates of A(10, 15) B(15, 15) C(30, 9).

lions [1.4K]

Check the picture below. so, that'd be the triangle's sides hmmm so let's use Heron's Area formula for it.

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{15}~,~\stackrel{y_2}{15}) ~\hfill a=\sqrt{[ 15- 10]^2 + [ 15- 5]^2} \\\\\\ ~\hfill \boxed{a=\sqrt{125}} \\\\\\ (\stackrel{x_1}{15}~,~\stackrel{y_1}{15})\qquad (\stackrel{x_2}{30}~,~\stackrel{y_2}{9}) ~\hfill b=\sqrt{[ 30- 15]^2 + [ 9- 15]^2} \\\\\\ ~\hfill \boxed{b=\sqrt{261}}$

$(\stackrel{x_1}{30}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{5}) ~\hfill c=\sqrt{[ 10- 30]^2 + [ 5- 9]^2} \\\\\\ ~\hfill \boxed{c=\sqrt{416}} \\\\[-0.35em] ~\dotfill$

$\qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{125}\\ b=\sqrt{261}\\ c=\sqrt{416}\\ s\approx 23.87 \end{cases} \\\\\\ A\approx\sqrt{23.87(23.87-\sqrt{125})(23.87-\sqrt{261})(23.87-\sqrt{416})}\implies \boxed{A\approx 90}$

6 0

2 years ago

How do I solve a problem like -8(n+3)+28=-5n-5

Xelga [282]

<span>-8(n+3)+28=-5n-5

-8n-24+28=-5n-5

</span>-8n+4=-5n-5

-8n+4-4=-5n-5-4

-8n=-5n-9

-8n+5n=-5n+5n-9

-3n=-9

-3n/-3=-9/-3

n=3

n=3 is the correct answer

8 0

3 years ago

Written as a simplified polynomial in standard form, what is the result when (2x - 7) ^ 2 is subtracted from 1?

zaharov [31]

Answer:

ans: -4( x-3 )( x-4 ) I.e -4( x² + x - 12 )

Step-by-step explanation:

as per question

1- (2x-7)²

= (1 + 2x - 7)(1- 2x + 7)

= ( 2x - 6)(-2x +8)

= -4(x-3)(x+4)

8 0

3 years ago

Which shows the list of numbers from least to greatest |-3|, | 3/2|, |-2|, |3.5|, -1?

nirvana33 [79]

First option is correct.

Hope it helped!!!!!!

4 0

3 years ago