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Dima020 [189]
4 years ago
14

The ratio of men to women working for a company is 5 to 8 . if there are 104 women working for the company, what is the total nu

mber of employees?
Mathematics
1 answer:
Oliga [24]4 years ago
7 0
The ration for women to men is: 

5:8 
104:x 

8x104=5x
832=5x 
832/5=x 
166.4 =x 

However, you cannot have 0.4 of a person, so the number of men is 166. 

Total number of employees are: 166+104=270 

Hope I helped :) 
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4(n+9)-3(2+n)<br> Help now plz
matrenka [14]

Answer:

n + 30

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
What is the slope of the graph of 4x - 8y = 11?<br> A. 1/2<br> B. 2<br> C. -2<br> D. - 1/2
Irina18 [472]
Hey there.. Lets solve this problem with steps

→ Basic Standard Formula
y = mx + b

→ Step 1 ( taking x to right side or arranging the equation in standard form)
-8y = -4x + 11

→Step 2 ( keeping y at it's own place by dividing both sides by -8)
y =\frac{-4}{-8} x - \frac{11}{8}
y = \frac{1}{2} x - <span>\frac{11}{8}

So, m = slope in standard formula
So, m = </span>\frac{1}{2}

Correct Option is A.

Hope this helped you..  :)
7 0
3 years ago
The linear density in a rod 5 m long is 10 x + 4 kg/m, where x is measured in meters from one end of the rod. Find the average d
hichkok12 [17]

The average density of the rod is  0.704 kg/m.

For given question,

We have been given the linear density in a rod 5 m long is 10 / x + 4 kg/m, where x is measured in meters from one end of the rod.

We need to find the

The length of rod is, L = 5 m.

The linear density of rod is, ρ = 10/( x + 4) kg/m

To find the average density we need to integrate the linear density from x₁ = 0 to x₂ = 5,  

The expression for the average density is given as,

⇒ ρ'

=\int\limits^5_0 {\rho} \, dx\\\\=\int\limits^5_0 {\frac{m}{L} } \, dx\\\\=\int\limits^5_0 {\frac{10}{5(x+4)} }\, dx\\\\=\int\limits^5_0 {\frac{2}{x+4} }\, dx                        ......................(1)

Using u = x + 4  

du = dx

u₁ = x₁ + 4

u₁ = 0 + 4

u₁ = 4

and

u₂ = x₂ + 4

u₂ = 5 + 4

u₂ = 9

By entering the values above into (1), we have:

⇒ ρ'

=2\int\limits^9_4 {\frac{1}{u} } \, du\\\\ = 2[(log~u)]_4^{9}\\\\=2[(log~9-log~4)]\\\\=2\times[0.352]

= 0.704

Thus, we can conclude that the average density of the rod is  0.704 kg/m.

Learn more about the average density here:

brainly.com/question/15118421

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3 0
2 years ago
I drove 320 miles in 5 hours, how many miles did I drive in 2 hours?​
vladimir2022 [97]

Answer:

128 miles

Step-by-step explanation:

320/5=x/2   640=5x    x=128

8 0
3 years ago
HELP NEED THIS FOR A TEST!!! 20 POINTS!!
steposvetlana [31]

Answer:

a.

capacity of car = 14 gallons

consumption of fuel in one day = 0.6 gallons

consumption of fuel in 14 days = 14 x 0.6 = 8.4 gallons

fuel remaining in car = 14 - 8.4 = 5.6 gallons

so they can drive the car without warning.

b.

consumption of fuel in one day = 0.6 gallons

consumption of fuel in 25 days = 25 x 0.6 = 15 gallons

fuel remaining in car = 14 - 15 = -1 gallons

so they can't drive the car without warning.

c.

the expression 14 - 0.6t represents remaining fuel in the vehicle, where t represents number of days.

d.

14 - 0.6t = 1.5

or - 0.6t = 1.5 - 14 = - 12.5

or t = -12.5 / - 0.6

or t = 20.8333 days

so he can drive 20 days without warning.                                                                                         E.

14 - 0.6t < 1.5

or t < 20.8333

here t represents number of days car can drive without warning light.

Step-by-step explanation:

The inequality is  

The maximum number of days that Diego's father can drive the car without the warning light coming on is 20 days

14 gallons-1.5 gallons=12.5 gallons  

we know that

If the remaining fuel is greater than  1.5 gallons Diego's father can drive the car without the warning light coming on  

so

Let

x ----> the number of days

 ----> inequality that represent the situation

Solve for x

The maximum number of days that Diego's father can drive the car without the warning light coming on is 20 days

6 0
3 years ago
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