Answer:
5 will come in blank
4KMnO₄ ----------> 2K₂O + 4MnO + 5O₂
Explanation:
Reaction:
4KMnO₄ ----------> 2K₂O + 4MnO + ____O₂
this reaction is the dissociation reaction in which KMnO₄ is break down into its component.
KMnO₄ upon dissociation gives Potassium oxide, manganese oxide and liberate oxygen
Balance Chemical Equation:
A balanced chemical equation is that in which the the number of the reactant atoms equal to the number of the product atom.
For example if the oxygen at the reactant side is 4, the number of oxygen should be 4 on the product side.
So for this purpose we have to balnce the reaction and number of atoms on each side of the arrow
if we see the given Equation
Numbers of atom on reactant Side:
K = 4
Mn = 4
O = 16
Numbers of atom on reactant Side:
K = 4
Mn = 4
O = 6 instead of blank oxygen molecule
so from the above data we have 10 oxygen less.
If we put the 5 in the blank then we will have 10 oxygen and equation will be balanced
So the balanced Equation will be
4KMnO₄ ----------> 2K₂O + 4MnO + 5O₂
Oil is less dense than water, so the difference would be its density. Water is a good solvent, which means It can dissolve other substances.
Answer:
The percentage composition of the elements of the compound in the three samples is the same.
Explanation:
<em>The law of definite proportions states that all pure samples of a particular chemical compound contain the same elements in the same proportion by mass.</em>
Sample A:
Mass of A = 4.31 g; mass of Z = 7.70 g
Total mass of sample = 12.01
Percentage mass of A in the sample = (4.31 * 100)/12.01 = 35.9 %
Percentage mass of Z in the sample = (7.70 * 100)/12.01 = 64.1 %
Sample B:
Percentage mass of A in the sample = 35.9 %
Percentage mass of Z in the sample = 64.1 %
Sample C:
Mass of A = 0.718 g; Total mass of sample = 2.00 g
mass of Z = mass of sample - mass of A = 2.00 g - 0.718 g = 1.282 g
Percentage mass of A in the sample = (0.718 * 100)/2.00 = 35.9 %
Percentage mass of Z in the sample = (1.282 * 100)/2.00 = 64.1 %
From the calculations, it can be seen that the percentage composition of the elements in the compound is the same for the three samples.
First, let's state the chemical reaction:
We can find the number of moles of Cl2 required to produce 0.0923 moles of AlCl3, doing a rule of three: 3 moles of Cl2 reacted produces 2 moles of AlCl3:
The calculation would be:
And the final step is to convert this number of moles to grams. Remember that the molar mass can be calculated using the periodic table, so the molar mass of Cl2 is 70.8 g/mol, and the conversion is:
The answer is that we need 9.770 grams of Cl2 to produce 0.0923 moles of AlCl3.
