The answer for the following answer is mentioned below.
- Therefore the mass of calcium nitrate (
Explanation:
To find the mass of calcium nitrate ( ) is :
No of calcium are 1
No of nitrogen are 2
No of oxygen are 6
= 
So therefore;
No of nitrogen are 2
No of oxygen are 6
Mass of ( ) :
molecular mass of calcium =40
molecular mass of nitrogen = 14
molecular mass of oxygen = 16
= (14×2) + (16×6)
= 28 + 96
= 124
= 40 + 124
<u><em></em></u><u><em> = 164 grams</em></u>
Therefore the mass of calcium nitrate ( ) is 164 grams
Answer:
0.0738 M
Explanation:
HNO3 +LiOH = LiNO3 + H2O
Number of moles HNO3 = number of moles LiOH
M(HNO3)*V(HNO3) = M(LiOH)*M(LiOH)
M(HNO3)*50.0mL = 0.100M*36.90 mL
M(HNO3) = 0.100*36.90/50.0 M = 0.0738 M
C6H6 is benzene, an organic compound. I would imagine it would be immiscible, since most organic compounds don’t dissolve in water very well.
Based on experiment 1:
Mass of Hg = 1.00 g
Mass of sulfide = 1.16 g
Mass of sulfur = 1.16 - 1.00 = 0.16 g
# moles of Hg = 1 g/200 gmol-1 = 0.005 moles
# moles of S = 0.16/32 gmol-1 = 0.005 moles
The Hg:S ratio is 1:1, hence the sulfide is HgS
Based on experiment 2:
Mass of Hg taken = 1.56 g
# moles of Hg = 1.56/200 = 0.0078
Mass of S taken = 1.02 g
# moles of S = 1.02/32 = 0.0319
Hence the limiting reagent is Hg
# moles of Hg reacted = # moles of HgS formed = 0.0078 moles
Molar mass of HgS = 232 g/mol
Therefore, mass of HgS formed = 0.0078 * 232 = 1.809 g = 1.81 g
