What is 2.105 rounded to the nearest inch?
1 answer:
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A) The degree of the first term is... 1
The degree of the second term is... 2
The degree of the third term is... 4
b) The leading term of the polynomial is... 7t⁴
The leading coefficient of the polynomial is... 7
c) The degree of the polynomial is... 4
The degree of the second term is... 2
The degree of the third term is... 4
b) The leading term of the polynomial is... 7t⁴
The leading coefficient of the polynomial is... 7
c) The degree of the polynomial is... 4
Given 
subject to the constraint 
Let
.
The gradient vectors of
and 
are:
and 
By Lagrange's theorem, there is a number
, such that
It can be seen that has local extreme values at the given region.
Let
The gradient vectors of
By Lagrange's theorem, there is a number
It can be seen that
Answer:
- arc BF = 76°
- ∠M = 31°
- ∠BGE = 121°
- ∠MFB = 111°
Step-by-step explanation:
(a) ∠FBM is the complement of ∠FBC, so is ...
∠FBM = 90° -52° = 38°
The measure of arc BF is twice this angle, so is ...
arc BF = 2∠FBM = 2(38°)
arc BF = 76°
__
(b) ∠M is half the difference between the measures of arcs BE and BF, so is ...
∠M = (1/2)(138° -76°) = 62°/2
∠M = 31°
__
(c) arc FC is the supplement to arc BF, so has measure ...
arc FC = 180° -arc BF = 180° -76° = 104°
∠BGE is half the sum of arcs BE and FC, so is ...
∠BGE = (1/2)(arc BE +arc FC) = (138° +104°)/2
∠BGE = 121°
__
(d) ∠MFB is the remaining angle in ∆MFB, so has measure ...
∠MFB = 180° -∠M -∠FBM = 180° -31° -38°
∠MFB = 111°
