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Artyom0805 [142]
2 years ago
15

State what additional information is required in order to know that the triangles are congruent for the reason given. If possibl

e, write the triangle congruence statement.
refer to attachment

Mathematics
2 answers:
Ierofanga [76]2 years ago
7 0

In this We need one more side congruent because one is common i.e FG. It is the line which is Dividing it into two triangles. The property used here is SAS or Side-angle-side Property.

Nataly_w [17]2 years ago
3 0

ASA stands for "angle, side, angle" and means that we have two triangles where we know two angles and the included side are equal. If two angles and the included side of one triangle are equal to the corresponding angles and side of another triangle, the triangles are congruent.

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Expand and simplify 5(3x+2)-2(4x-1)
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5(3x+2)-2(4x-1)

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= 7x+12

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You estimate that a jar contains 68 marbles.The actual number of marbles is 60.Find the percent error.Round your answer to the n
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When Emilio drives his truck, the miles are varied directly with the
Inga [223]

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40 months

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2 years ago
Perpendicular to the line y =6 - 3x; passes through (-3, -1)
madam [21]

Answer:

y=\frac{1}{3}x

Step-by-step explanation:

<u>Perpendicular lines</u>

Perpendicular lines have slopes whose product is -1.  In other words, to find a line that is perpendicular to a given line, the new line must have a that is the opposite reciprocal of the original line.

<u>Passing through a point</u>
Additionally, if a line contains a point, then the point must be a solution to the equation (meaning, when you plug in the "x" and "y", the equation must be true).

<u>Finding our perpendicular line</u>

<u>Work on slope first</u>

To find the slope of the original line, rewrite the original line in slope-intercept form: y=mx+b

y=6-3x\\y=6+(-3x)\\y=(-3x)+6\\y=-3x+6\\y=-\frac{3}{1}x+6

In this form, the slope is the number multiplied to the "x", so the original slope is -3/1.

Thus, the slope of the new perpendicular line will be the opposite reciprocal of -3/1 ... which is 1/3.

Writing what we do know about the new perpendicular line, we have y=\frac{1}{3}x+b

<u>Making sure it passes through the point</u>
This new line is also supposed to contain the point (-3,-1), so (-3,-1) must be a solution to the equation, for whatever constant-value the "b" is.  To find out the "b", substitute the known quantities, and solve:

-1=\frac{1}{3} (-3)+b\\-1=-1+b\\(-1)+1=(-1+b)+1\\0=b

Substituting this into our equation:

y=\frac{1}{3}x+(0)\\y=\frac{1}{3}x

<u>Conclusion</u>

So, the equation for a line that is perpendicular to the original line y=6-3x, and that also passes through (-3,-1) is y=\frac{1}{3}x

6 0
1 year ago
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