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Naddik [55]
2 years ago
6

If a line has a midpoint at (2,5), and the endpoints are (0,0) and (4,y), what is the value of y? Please explain each step for a

better understanding:)
Mathematics
1 answer:
Dovator [93]2 years ago
3 0

Answer:

y = 10

Step-by-step explanation:

To find the y coordinate of the midpoint, take the y coordinates of the endpoints and average

(0+y)/2 = 5

Multiply each  die by 2

0+y = 10

y = 10

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-4h - 6 = 22 what does h equal
daser333 [38]
-4h -6 = 22
To solve this, we need to get -4h by itself and then simplify.
-4h -6 = 22
Add 6 to both sides.
-4h = 28
Divide both sides by -4.
h = -7.

I hope this helps!
8 0
3 years ago
Really need help guys!<br> Love you if you can solve them wiz steps!!!!
Marta_Voda [28]

Answer:

Step-by-step explanation:

x^2+y^2-8x+4y+4=0\\\\a)\\\\x^2-8x+y^2+4y+4=0\\\\x^2-2*x*4+(y^2+2*y*2+2^2)=0\\\\x^2-2*x*4+4^2+(y+2)^2=4^2\\\\(x-4)^2+(y+2)^2=4^2\\

Hence,

The radius of the circle is 4 units, coordinates of its centre are (4,-2).

b)\\\\y=0\\x^2+0^2-8x+4*0+4=0\\x^2-8x+4=0\\a=1\ \ \ \ b=-8\ \ \ \ c=4\\D=(-8)^2-4*1*4\\D=64-14\\D=48\\\sqrt{D}=\sqrt{48} \\ \sqrt{D}=\sqrt{16*3} \\\sqrt{D}=\sqrt{4^2*3}  \\\sqrt{D}=4\sqrt{3}  \\\displaystyle\\x=\frac{-(-8)б4\sqrt{3} }{2*1} \\\\x=\frac{8б4\sqrt{3} }{2} \\x_1=4-2\sqrt{3} \\x_2=4+2\sqrt{3}

c)\\\\A(6,2\sqrt{3}-2)\\ (x-4)^2+(y+2)^2=4^2\\(6-4)^2+(2\sqrt{3} -2+2)^2=16\\2^2+(2\sqrt{3} )^2=16\\4+2^2*(\sqrt{3})^2=16\\ 4+4*3=16\\4+12=16\\16\equiv16

d)\\A(6,2\sqrt{3}-2)}\\\sqrt{3} x+3y=\\\sqrt{3}(6)+3(2\sqrt{3} -2)=\\ 6\sqrt{3}+6\sqrt{3} -6=\\ 12\sqrt{3}-6

5 0
1 year ago
What is the smallest integer that can be divided by the product of a prime number and 7 while yielding a prime number?
11111nata11111 [884]

Answer:

(D). 28

Step-by-step explanation:

We have been given that the smallest integer that can be divided by the product of a prime number and 7 while yielding a prime number.  

We know that smallest prime is 2. The product of 2 and 7 is 14.

Let us divide our given numbers by 14.

(A) 7.

\frac{7}{14}=\frac{1}{2}

The quotient is not a integer or prime number.

(B). 14

\frac{14}{14}=1

We know that 1 is not a prime number.

(C) 24.

\frac{24}{14}=\frac{12}{7}

The quotient is not a integer or prime number.

(D). 28

\frac{28}{14}=2

Since 2 is a prime number, therefore, 28 is the smallest integer that can be divided by the product of a prime number and 7 and yield a prime number.

4 0
3 years ago
You pick a card at random from an ordinary deck of 52 cards. If the card is an ace, you get 9 points; if not, you lose 1 point.
denis-greek [22]

Answer:

Step-by-step explanation:

In a deck of 52 cards there are 4 aces.

Therefore the probability of obtaining an ace is:

P (x) = 4/52

The probability of not getting an ace is:

P ('x) = 1-4 / 52

P ('x) = 48/52

In this problem the number of aces obtained when extracting cards from the deck is a discrete random variable.

For a discrete random variable V, the expected value is defined as:

Where V is the value that the random variable can take and P (V) is the probability that it takes that value.

We have the following equation for the expected value:

In this problem the variable V can take the value V = 9 if an ace of the deck is obtained, with probability of 4/52, and can take the value V = -1 if an ace of the deck is not obtained, with a probability of 48 / 52

7 0
3 years ago
PLZ HELP ME ILL MARK AS BRAINLEIST
lora16 [44]

Answer: 72.22

rounded to the nearest tenth would be 72.2

Step-by-step explanation:

You multiply 23 and 3.14

3 0
3 years ago
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