Assuming this triangle is a right triangle, 52 degrees.
Answer:
C. Elizabeth wants to estimate the mean vacation days of coworkers at her company. She collects data by selecting a random group of coworkers within her department.
Step-by-step explanation:
Sampling Bias is case, in which some section of population have higher or lower chance of being selected in sample than others.
'Elizabeth wants to estimate the mean vacation days of coworkers at her company. She collects data by selecting a random group of coworkers within her department'. This case is of Convenience Sampling, where person selects sample only as per his/ her convenience.
Elizabeth has conveniently chosen sample workers from her department, so they have higher chance of being in sample, others have lesser chance. Hence, this is Sampling Bias
:
5
:
3x+2=17
-2 -2
3x=15
/3 /3
x=5
Most of the information's that are required for solving this question is already given in the question. It is important to check them minutely before trying to solve the problem in hand.
Amount of prize money won by the darts team = 1750 pounds
The amount of money that needs to be saved = 70 pounds
Then
Amount of money remaining after savings = (1750 - 70) pounds
= 1680 pounds
The number of team members in the darts team = 14
So
The amount of money
that each members of the darts team gets = 1680/14
= 70 pounds
From the above deduction we can easily conclude that each member of the darts teams will get an amount of 70 pounds.
The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is 
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:

where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:

Hence, the half life of the sample of phosphorus-32 is 