3 years ago

Help me please and I need this asap please

Mathematics

1 answer:

frozen [14]3 years ago

6 0

Answer:

The answer is -77 you just multiplying then subtracting

You might be interested in

Which is equivalent to (3/125)*?<br><br><br> answer : a 1251/3x

sashaice [31]

Answer:

1/50

Step-by-step explanation:

4 0

3 years ago

A patrolman gives a driver a speeding ticket if the driver’s speed is greater than 15% over the posted speed limit. If the speed

daser333 [38]

Answer:

No faster than 46 mph

Step-by-step explanation:

40*.15=6

6+40=46

(This is assuming they can go 15% over the speed limit and not that the car needs to be below 15% over the soeed limit)

3 0

4 years ago

PLS HELP 50 POINTS!!

Leno4ka [110]

Step-by-step explanation:

everything can be found in the picture above. Hope this helps

7 0

3 years ago

Read 2 more answers

A box on a 20 degree incline is shown with vectors radiating from a point in the center of the box. The first vector points up a

Finger [1]

The images to solve this problem is in the attachment.

Answer: $F_{fs}$ = 671.0 N; $F_{N}$ = 300 N

Step-by-step explanation: From the image in the attachment and knowing that the box is in equilibrium, i.e., the "sum" of all the forces is 0, it is possible to conclude that:

$F_{fs}$ = $F_{gx}$ and $F_{N}$ = $F_{gy}$

Using trigonometry, shown in the second attachment, the values for each force are:

Force of Static Friction

sin 20° = $\frac{F_{gx} }{F_{g} }$

$F_{gx}$ = $F_{g}$ . sin(20)

$F_{gx}$ = 735.0.913

$F_{gx}$ = 671.0

Normal Force

cos 20° = $\frac{F_{gy} }{F_{g} }$

$F_{gy}$ = $F_{g}$ . cos (20)

$F_{gy}$ = 735.0.408

$F_{gy}$ = 300

The force of static friction is 671N and normal force is 300N

8 0

3 years ago

Read 2 more answers

3.1 , 3.4 , 3.25 , 3.33 from greatest to least

BlackZzzverrR [31]

Answer:

3.1 3.25 3.33 3.4

Step-by-step explanation:

4 0

4 years ago