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4 years ago

Write the reflation ship between the value of the given digits 6s in 660

1 answer:

5 0

Hello Srahman1183 i get how adjetated u must be feeling right now having to wait 6 days to get this answer im about to give u but whatever. The relationship between them istheyare both partof the powers of ten, the first 6 is inthe 100 place and the second 6 is in the 10 place, hope this helped

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Joaquin and Trisha are playing a game in which the lower median wins the game. Their scores are shown below. Joaquin's scores: 7

alekssr [168]

Answer:

Step-by-step explanation:

Given

Joaquin's score is $75,72,85,62,58,91$

and Trisha's score is $92,90,55,76,91,74$

Arranging score in order of value we get

Joaquin's : $58,62,72,75,85,91$

Trisha's : $55,74,76,90,91,92$

as no of values is even therefore their median is

Joaquin's $=\frac{72+75}{2}=73.5$

Trisha's $=\frac{76+90}{2}=83$

Therefore median of Joaquin's is lower

Thus Joaquin wins the game

5 0

3 years ago

Read 2 more answers

What's 2|-9| - |-2|?

UNO [17]

Answer:

Step-by-step explanation:

First, simplify by finding the absolute values:

2|-9| - |-2|

2(9) - (2)

Then, simplify this by multiplying 2 and 9:

18 - 2

= 16

So, the answer is 16

3 0

3 years ago

Please help i’ll give brainliest

Setler79 [48]

Answer:

range

Step-by-step explanation:

*JUST AND EDUCATED GUESS* but id say range

7 0

3 years ago

Log(x-2)+log2=2logy<br>log(x-3y+3)=0

In-s [12.5K]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}\log(x-2)+\log2=2\log y&(1)\\\log(x-3y+3)=0&(2)\end{array}\right$

$===========================\\\text{DOMAIN:}\\\\x-2>0\to x>2\\y>0\\x-3y+3>0\to x-3y>-3\\=====================\\\\\text{We know:}\ \log_ab=c\iff a^c=b,\\\\\text{therefore}\ \log_ab=0\iff a^0=b\to b=1\\\\\text{From this we have}\\\\\log(x-3y+3)=0\iff x-3y+3=1\qquad\text{add}\ 3y\ \text{to both sides}\\\\x+3=3y+1\qquad\text{subtract 3 from both isdes}\\\\\boxed{x=3y-2}\qquad(*)\\\\\text{Substitute it to (1)}$

$\log(3y-2-2)+\log2=2\log(y)\qquad\text{use}\ \log_ab^n=n\log_ab\\\\\log(3y-4)+\log2=\log(y^2)\qquad\text{subtract}\ \log(y^2)\ \text{from both sides}\\\\\log(3y-4)+\log2-\log(y^2)=0\\\\\text{Use}\ \log_ab+\log_ac=\log_a(bc)\ \text{and}\ \log_ab-\log_ac=\log_a\dfrac{b}{c}\\\\\log\dfrac{(3y-4)(2)}{y^2}=0\qquad\text{use}\ \log_ab=0\Rightarrow b=1\\\\\dfrac{(3y-4)(2)}{y^2}=1\iff y^2=(3y-4)(2)\\\\\text{Use the distributive property}\ a(b+c)=ab+ac$

$y^2=(3y)(2)+(-4)(2)\\\\y^2=6y-8\qquad\text{subtract}\ 6y\ \text{from both sides}\\\\y^2-6y=-8\qquad\text{add 8 to both sides}\\\\y^2-6y+8=0\\\\y^2-2y-4y+8=0\\\\y(y-2)-4(y-2)=0\\\\(y-2)(y-4)=0\iff y-2=0\ \vee\ y-4=0\\\\\boxed{y=2\ \vee\ y=4}\in D$

$\text{Put the values of}\ y\ \text{to }\ (*):\\\\\text{for}\ y=2:\\\\x=3(2)-2\\\\x=6-2\\\\\boxed{x=4}\in D\\\\\text{for}\ y=4:\\\\x=3(4)-2\\\\x=12-2\\\\\boxed{x=10}\in D$

4 0

3 years ago

The graph translated horizontally two units right, vertically four units down and reflected across x-axis from its parent functi

Keith_Richards [23]

Parent Function: f(x) = x^2

Right 2 units: f(x) = (x^2 - 2)

Down 4 units: f(x) = (x^2 - 2) - 4

Reflection over x-axis: f(x) = - (x^2 -2) + 4

Answer: f(x) = - (x^2 -2) + 4

3 0

3 years ago