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RideAnS [48]
3 years ago
13

Need help in my quiz bc I want to passsss pls send helps

Mathematics
1 answer:
Whitepunk [10]3 years ago
6 0

Answer:

pethagoru

8^2 + 6^2= 100

pethagorus theory is a^2+b^2=c^2.

a^2 = base

b^2= side

c^2= hypotenuse

You might be interested in
THE X-INTERCEPT OF THE LINE X=3.5 IS
tiny-mole [99]
Well.. for the equation x= 3.5, let's take a look at its values
\bf \begin{array}{lrlll}
x&y\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
3.5&-\infty\\
3.5&-1,000,000\\
3.5&-1,000\\
3.5&-100\\
3.5&-10\\
3.5&-1\\
3.5&0\\
3.5&1\\
3.5&10\\
3.5&100\\
3.5&1,000\\
3.5&1,000,000\\
3.5&1+\infty
\end{array}

so.. notice.. no matter what "y" is, "x"  will always be 3.5,
so is really just a horizontal line, thus, look at the picture below

8 0
4 years ago
the initial vertical velocity of a rocket shot straight up is 42 meters per second. How long does it take for the rocket to retu
Snowcat [4.5K]
It takes 4.3 seconds for the rocket to return to earth.

The equation is:
0=-9.8t^2+v_0t+h_0
where -9.8m/sec² is the acceleration due to gravity, v₀ is the initial velocity, and h₀ is the initial height.  We will go from the assumption that the rocket is launched from the ground, so h₀=0, and we are told that the initial velocity, v₀, is 42.  This gives us:

0=-9.8t^2+42t

We will use the quadratic formula to solve this.  The quadratic formula is:
x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Plugging in our information we have:
t=\frac{-42\pm \sqrt{42^2-4(-9.8)(0)}}{2(-9.8)}
\\
\\=\frac{-42\pm \sqrt{1764-0}}{-19.6}
\\
\\=\frac{-42\pm \sqrt{1764}}{-19.6}
\\
\\=\frac{-42\pm 42}{-19.6}=\frac{-42-42}{-19.6} \text{ or } \frac{-42+42}{-19.6}
\\
\\=\frac{-84}{-19.6}\text{ or }\frac{0}{-19.6}
\\
\\=4.3\text{ or }0

x=0 is when the rocket is launched; x=4.3 is when the rocket lands.
8 0
4 years ago
The measure of one acute angle in this right triangle is 45°.
maks197457 [2]

Answer:

45°

Step-by-step explanation:

90-45=45°

3 0
3 years ago
Read 2 more answers
2. A student on the track team runs 45 minutes each day as a part of her training. She
fomenos

Answer:

D

Step-by-step explanation:

The basic equation to solve this would be D = RT, which is

D is Distance

R is Rate (speed)

T is time

To find total distance D, we can find individual distances for two legs of the whole.

First Leg:

R = 8

T = a

D = 8a

Second Leg:

R = 7.5

T = b

D = 7.5b

Total distance D is:

D = 8a + 7.5b

Moreover, we know student runs 45 minutes in total hence a + b = 45 or we can say a = 45 - b, so we can replace this in the equation found:

D = 8a + 7.5b

D = 8(45 - b) + 7.5b

Answer choice D is right.

8 0
4 years ago
How do you find vertical asymptotes?
Keith_Richards [23]
You just have to set the denominator to zero and solve for x
7 0
3 years ago
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