No the following coordinates do not show a function because of the y-values. In the pairs that you have, (3,5) and (0,5) have the y-values of "5" that are repeating.
Hope this helps. I learned that in math.
Answer:
Step-by-step explanation:
Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?
Let p(x)=kpx+dp and q(x)=kqx+dq than
f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7
p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7
(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)
So you want:
−2kpk2q=0
and
kpkq=−1
and
2kpd2p−3kpdq+7=0
Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .
Answer: there are no such linear functions.
The area of a trapezoid with base lengths 7 in and 19 in is given by
A = (1/2)(b1 + b2)h
A = (1/2)(7 +19)·7 = 91
The appropriate choice is
D. 91 in²
_____
It can also be figured by adding the area of the 7 in square (49 in²) to the area of the 7×12 in right triangle (42 in²).
<h3>Answers:</h3><h3>First box = 57.14</h3><h3>Second box = 80</h3>
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Explanation:
If you save 65%, then you pay the remaining 35%
0.35x is the final price when x is the original price
0.35x = 20 solves to x = 57.14 approximately after dividing both sides by 0.35
57.14 goes in the first box
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This must mean 80 goes in the other box.
Here's the steps on how to get 80
If you save 75% then you pay the remaining 25%
0.25x = 20
x = 20/0.25
x = 80
80 goes in the second box
Answer:
She pays $15.74
Step-by-step explanation:
Divide 425 by 27
