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EleoNora [17]
3 years ago
12

What is the greatest possible product of a 2 digit number and a 1 digit number

Mathematics
1 answer:
Molodets [167]3 years ago
3 0
891
because 99(the greatest 2 digit number)*9(the greatest 1 digit number)=891
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Answer:

\displaystyle k = 6

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Algebra I</u>

  • Functions
  • Function Notation

<u>Algebra II</u>

  • Piecewise Functions<u> </u>

<u>Calculus</u>

  • Limits
  • Continuity

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

Continuous at x = 2

\displaystyle f(x) = \left \{ {{2x^2 \ if \ x < 2} \atop {x + k \ if \ x \geq 2}} \right.

<u>Step 2: Solve for </u><em><u>k</u></em>

  1. Definition of Continuity:                                                                                   \displaystyle  \lim_{x \to 2^+} 2x^2 =  \lim_{x \to 2^-} x + k
  2. Evaluate limits:                                                                                                  \displaystyle 2(2)^2 =  2 + k
  3. Evaluate exponents:                                                                                         \displaystyle 2(4) =  2 + k
  4. Multiply:                                                                                                             \displaystyle 8 =  2 + k
  5. [Subtraction Property of Equality] Subtract 2 on both sides:                        \displaystyle 6 = k
  6. Rewrite:                                                                                                             \displaystyle k = 6

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Limits - Continuity

Book: College Calculus 10e

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