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jekas [21]
3 years ago
13

Help please!! Step by step!!

Mathematics
1 answer:
GarryVolchara [31]3 years ago
5 0

Answer:

P(Ice Cream|Frogtown) = 67.4\%

Step-by-step explanation:

Given

The attached plot

Required

P(Ice Cream|Frogtown)

This is calculated as:

P(Ice Cream|Frogtown) = \frac{P(Ice\ Cream\ n\ Frogtown)}{P(Frogtown)}

From the attachment;

P(Ice\ Cream\ n\ Frogtown) = 0.31

P(Frogtown) = 0.31 + 0.15 = 0.46

So, we have:

P(Ice Cream|Frogtown) = \frac{P(Ice\ Cream\ n\ Frogtown)}{P(Frogtown)}

P(Ice Cream|Frogtown) = \frac{0.31}{0.46}

P(Ice Cream|Frogtown) = 0.6739

Express as percentage

P(Ice Cream|Frogtown) = 0.6739 * 100\%

P(Ice Cream|Frogtown) = 67.39\%

P(Ice Cream|Frogtown) = 67.4\% -- approximated

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puteri [66]
Three million five hundred thousand or three and a half million
5 0
3 years ago
A computer programming team has 13 members. a. How many ways can a group of seven be chosen to work on a project? b. Suppose sev
Julli [10]

Answer:

1716 ;

700 ;

1715 ;

658 ;

1254 ;

792

Step-by-step explanation:

Given that :

Number of members (n) = 13

a. How many ways can a group of seven be chosen to work on a project?

13C7:

Recall :

nCr = n! ÷ (n-r)! r!

13C7 = 13! ÷ (13 - 7)!7!

= 13! ÷ 6! 7!

(13*12*11*10*9*8*7!) ÷ 7! (6*5*4*3*2*1)

1235520 / 720

= 1716

b. Suppose seven team members are women and six are men.

Men = 6 ; women = 7

(i) How many groups of seven can be chosen that contain four women and three men?

(7C4) * (6C3)

Using calculator :

7C4 = 35

6C3 = 20

(35 * 20) = 700

(ii) How many groups of seven can be chosen that contain at least one man?

13C7 - 7C7

7C7 = only women

13C7 = 1716

7C7 = 1

1716 - 1 = 1715

(iii) How many groups of seven can be chosen that contain at most three women?

(6C4 * 7C3) + (6C5 * 7C2) + (6C6 * 7C1)

Using calculator :

(15 * 35) + (6 * 21) + (1 * 7)

525 + 126 + 7

= 658

c. Suppose two team members refuse to work together on projects. How many groups of seven can be chosen to work on a project?

(First in second out) + (second in first out) + (both out)

13 - 2 = 11

11C6 + 11C6 + 11C7

Using calculator :

462 + 462 + 330

= 1254

d. Suppose two team members insist on either working together or not at all on projects. How many groups of seven can be chosen to work on a project?

Number of ways with both in the group = 11C5

Number of ways with both out of the group = 11C7

11C5 + 11C7

462 + 330

= 792

8 0
2 years ago
Can anybody show me the steps to answering this question? 7x - 2z = 4 - xy<br> (solve for x)
Fed [463]

Answer: 2z+4/y+7

Step-by-step explanation:

We are trying to solve for x

7x-2z=4-xy

Add xy to both sides:

7x-2z+xy=-xy+4+xy= xy+7x-2z=4

Then you add 2z to both sides:

xy+7x-2z+2z=4+2z

xy+7x=2z+4

Then you factor out variable x

x(y+7)=2z+4

You divide both sides by y+7

x(y+7)/y+7= 2z+4/y+7

Which we would get x=2z+4/y+7

8 0
3 years ago
PLEASE HELP I DONT KNOw all THE DEFINITIONS TO THESE- MARK BRAINLIEST TOO
frozen [14]

Answer:

Factor

−

1

out of

−

3

x

2

+

4

x

−

7

.

−

(

3

x

2

−

4

x

+

7

)

Step-by-step explanation:

4 0
3 years ago
6. f(x) = x ^ 2 + 2x g(x) = 3x ^ 2 - 1
AVprozaik [17]

Answer:

3x^2+1

Step-by-step explanation:

7 0
3 years ago
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