All categories

3 years ago

I need help I don't understand this

Mathematics

2 answers:

Stella [2.4K]3 years ago

5 0

You plug in the numbers to the equation A2+B2=C2

borishaifa [10]3 years ago

3 0

It's so simple though.

You might be interested in

The sum of a number x and 5 equals 14

pav-90 [236]

Answer:

x=9

Step-by-step explanation:

Since x+5=14, then you would subtract 5 from 14. 14-5=9. So that means x equals 9.

3 0

3 years ago

Read 2 more answers

Giải phương trình sau:<br> sinx=1/2

cupoosta [38]

Answer: $\begin{bmatrix}\mathrm{Radians:}\:&\:x=\frac{\pi }{6}+2\pi n,\:x=\frac{5\pi }{6}+2\pi n\:\\ \:\mathrm{Degrees:}&\:x=30^{\circ \:}+360^{\circ \:}n,\:x=150^{\circ \:}+360^{\circ \:}n\end{bmatrix}$

Step-by-step explanation:

$\sin \left(x\right)=\frac{1}{2}$

$x=\frac{\pi }{6}+2\pi n,\:x=\frac{5\pi }{6}+2\pi$

4 0

2 years ago

Read 2 more answers

potatoes - Samples: Assume the weights of Farmer Carl's potatoes are normally distributed with a mean of 8.0 ounces and a standa

EleoNora [17]

24 because 42 \ 6 is 24

4 0

3 years ago

Started business whit cash Rs 250000 and Machinery Rs 200000<br>Accounting equation

oksano4ka [1.4K]

$\huge\purple{Answer}$

In case there is no double entry system is followed, profit can be calculated by comparing the opening and closing capital. In the given situation this can be calculated as:

Opening Capital Rs.200000

Add: Capital Introduced Rs.200000

Add: Profit for the year Rs. 250000

Less: Loss for the year Rs.NIL

Less: Drawings Rs. 30000

--------------------

Capital at the end of the year Rs.620000

-------------------

Loan taken is a liability and loan given is asset, that will not affect the capital.

<h2>ƑƠԼԼƠƜ MЄ❤</h2>

7 0

2 years ago

Read 2 more answers

The weight of baby goats is believed to be Normally distributed, with a mean of 5.75 pounds. The average weight of a random samp

Julli [10]

Answer:

The standard error of the mean is 0.0783.

Step-by-step explanation:

The Central Limit Theorem helps us find the standard error of the mean:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .