Answer:
The amount of nuts is 16 kg and cereal mixture is 44 kg to obtain 60 kg of a mix that will sell for $1.40 per kg
Step-by-step explanation:
Let
x=nuts at $2.50 per kg
y=cereal at $1 per kg
x+y=60 kg (1)
2.50x+y=1.40(60) (2)
From (1)
x=60-y
Substitute x=60-y into (2)
2.50x+y=1.40(60)
2.50(60-y)+y=84
150-2.5y+y=84
-1.5y=84-150
-1.5y=-66
Divide both sides by -1.5
y=44 kg
Substitute y=44 into (1)
x+y=60
x+44=60
x=60-44
=16
x=16 kg
Answer:
13
Step-by-step explanation:
14x-1=x+12
13x=13
x=1
x=12
1=12
=13
Let X be the number of female employee. Let n be the sample size, p be the probability that selected employee is female.
It is given that 45% employee are female it mean p=0.45
Sample size n=60
From given information X follows Binomial distribution with n=50 and p=0.45
For large value of n the Binomial distribution approximates to Normal distribution.
Let p be the proportion of female employee in the given sample.
Then distribution of proportion P is normal with parameters
mean =p and standard deviation =
Here we have p=0.45
So mean = p = 0.45 and
standard deviation =
standard deviation = 0.0642
Now probability that sample proportions of female lies between 0.40 and 0.55 is
P(0.40 < P < 0.45) =
= P(-0.7788 < Z < 1.5576)
= P(Z < 1.5576) - P(Z < -0.7788)
= P(Z < 1.56) - P(Z < -0.78)
= 0.9406 - 0.2177
= 0.7229
The probability that the sample proportion of females is between 0.40 and 0.55 is 0.7229
Answer:
12,500,000. You simply move the decimal point over to the right 7 times.
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