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3 years ago

2/9 equals what fraction of 54

2 answers:

7 0

Its 12 because 9 goes into 54 6 times and 6+6 = 12 so its 12
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Can you understand that because im bad at explaining? lol

musickatia [10]3 years ago

5 0

Try This: ([59x4]+2)

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What are TWO different ways you know when you are finished dividing?

vfiekz [6]

You know you are finished dividing when you can no longer simply & when you plug it back in to check the answer

7 0

2 years ago

The two triangles illustrated below are similar. What are the values of x and y?

poizon [28]

Answer:

${ \bf{by \: relations : }} \\ { \tt{ \frac{28}{7} = \frac{x}{8} }} \\ \\ { \tt{x = \frac{28 \times 8}{7} }} \\ x = 32 \\ \\ { \tt{y = 83 \degree}}$

5 0

2 years ago

What is the equation of a line, in general form, with a slope of -2 and a y-intercept of 8?

Ksenya-84 [330]

Answer:

y = -2x + 8 is the answer to the question

8 0

3 years ago

Find the general solution of the differential equation and check the result by differentiation. (Use C for the constant of integ

atroni [7]

Answer: $y=Ce^(^3^t^{^9}^)$

Step-by-step explanation:

Beginning with the first differential equation:

$\frac{dy}{dt} =27t^8y$

This differential equation is denoted as a separable differential equation due to us having the ability to separate the variables. Divide both sides by 'y' to get:

$\frac{1}{y} \frac{dy}{dt} =27t^8$

Multiply both sides by 'dt' to get:

$\frac{1}{y}dy =27t^8dt$

Integrate both sides. Both sides will produce an integration constant, but I will merge them together into a single integration constant on the right side:

$\int\limits {\frac{1}{y} } \, dy=\int\limits {27t^8} \, dt$

$ln(y)=27(\frac{1}{9} t^9)+C$

$ln(y)=3t^9+C$

We want to cancel the natural log in order to isolate our function 'y'. We can do this by using 'e' since it is the inverse of the natural log:

$e^l^n^(^y^)=e^(^3^t^{^9} ^+^C^)$

$y=e^(^3^t^{^9} ^+^C^)$

We can take out the 'C' of the exponential using a rule of exponents. Addition in an exponent can be broken up into a product of their bases:

$y=e^(^3^t^{^9}^)e^C$

The term e^C is just another constant, so with impunity, I can absorb everything into a single constant:

$y=Ce^(^3^t^{^9}^)$

To check the answer by differentiation, you require the chain rule. Differentiating an exponential gives back the exponential, but you must multiply by the derivative of the inside. We get:

$\frac{d}{dx} (y)=\frac{d}{dx}(Ce^(^3^t^{^9}^))$

$\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*\frac{d}{dx}(3t^9)$

$\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*27t^8$

Now check if the derivative equals the right side of the original differential equation:

$(Ce^(^3^t^{^9}^))*27t^8=27t^8*y(t)$

$Ce^(^3^t^{^9}^)*27t^8=27t^8*Ce^(^3^t^{^9}^)$

QED

I unfortunately do not have enough room for your second question. It is the exact same type of differential equation as the one solved above. The only difference is the fractional exponent, which would make the problem slightly more involved. If you ask your second question again on a different problem, I'd be glad to help you solve it.

7 0

2 years ago

Kiran and Clare live 24 miles away from each other along a rail trail. One Saturday, the two friends started walking toward each

vivado [14]

Answer:

They would be 44.6 miles apart

Step-by-step explanation:

Here, we want to calculate how far they will be in 1 hour

Mathematically;

Distance = speed * time

In 1 hour, Kiran would have traveled a distance of 3 * 1 = 3 miles

While Clare would have traveled a distance of 3.4 * 1 = 3.4 miles

Now, we want to calculate how far apart they would be

On the 24 miles trail, Kiran would be at a distance of 21 miles to the other end

On the 24 miles Claire would be at a distance of 20.6 miles

So how far apart they would be is

24 miles + 20.6 miles = 44.6 miles

3 0

2 years ago