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ExtremeBDS [4]
3 years ago
9

Select the multiplication sentence that applies the commutative property of multiplication to the example.

Mathematics
1 answer:
Travka [436]3 years ago
4 0

we are given

6 × 8 = 48

we know that

commutative property of multiplication:

a \times b =b \times a

now, we will verify each options

option-A:

we have

6 × 8 = 48

now, we can find it's commutative

so, we get

8 × 6 = 48

so, this is TRUE

option-B:

we have

6 × 8 = 48

now, we can find it's commutative

so, we get

8 × 6 = 48

so, this is FALSE

option-C:

we have

6 × 8 = 48

now, we can find it's commutative

so, we get

8 × 6 = 48

so, this is FALSE



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Let, total number of T-shirts are x.

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Answer:

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Step-by-step explanation: Hope this helps!

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I really need help! can someone help me
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A skier has decided that on each trip down a slope, she will do 3 more jumps than before. On her first trip she did 5 jumps. Der
taurus [48]
Since we are already given the amount of jumps from the first trial, and how much it should be increased by on each succeeding trial, we can already solve for the amount of jumps from the first through tenth trials. Starting from 5 and adding 3 each time, we get: 5 8 (11) 14 17 20 23 26 29 32, with 11 being the third trial.

Having been provided 2 different sigma notations, which I assume are choices to the question, we can substitute the initial value to see if it does match the result of the 3rd trial which we obtained by manual adding.

Let us try it below:

Sigma notation 1:

  10
<span>   Σ (2i + 3)
</span>i = 3

@ i = 3

2(3) + 3
12

The first sigma notation does not have the same result, so we move on to the next.

  10
<span>   Σ (3i + 2)
</span><span>i = 3
</span>
When i = 3; <span>3(3) + 2 = 11. (OK)
</span>
Since the 3rd trial is a match, we test it with the other values for the 4th through 10th trials.

When i = 4; <span>3(4) + 2 = 14. (OK)
</span>When i = 5; <span>3(5) + 2 = 17. (OK)
</span>When i = 6; <span>3(6) + 2 = 20. (OK)
</span>When i = 7; 3(7) + 2 = 23. (OK)
When i = 8; <span>3(8) + 2 = 26. (OK)
</span>When i = 9; <span>3(9) + 2 = 29. (OK)
</span>When i = 10; <span>3(10) + 2 = 32. (OK)

Adding the results from her 3rd through 10th trials: </span><span>11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 = 172.
</span>
Therefore, the total jumps she had made from her third to tenth trips is 172.


3 0
3 years ago
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