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Gelneren [198K]
3 years ago
6

How to prove this using trig identities?

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
7 0

Step-by-step explanation:

tanB + cotB = (sinB)/(cosB) + (cosB)/(sinB)

 

                      = (sin2B + cos2B)/[(cosB)(sinB)]

 

                       = 1/[(cosB)(sinB)]

 

                        = (1/cosB)(1/sinB)

 

                        = (secB)(cscB)

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\bf \textit{Law of sines}
\\ \quad \\
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