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3 years ago

6

santa has lots of mixed up socks in his sack. if he has 6 green socks, 4 gold socks, 8 black socks and 2 red socks, what is the

minimum he needs to pull out to get a matching pair?

2 answers:

REY [17]3 years ago

6 0

This does not state with or without replacement so I did it without replacement.

marysya [2.9K]3 years ago

4 0

2, as you need a pair

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PLS HELP.... If 4x^2 + bx + 9 = 0, where b is the constant, has exactly one solution, what is a possible value of b ?

IgorLugansk [536]

You can use the discriminant rule, which is :
b^2 -4ac
“exactly one solution” means that it is equal to zero
so:
b^2 -4(4)(9)=0
b^2 -4(36)=0
b^2 -144=0
b^2=144
square root both sides
b=12 or -12

hope this helps !

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2 years ago

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if A and B together can do a piece of work in 10 days and B along can do it in 15 days, how many part of the work does A complet

anzhelika [568]

Answer:

1/5

Step-by-step explanation:

Well work can be defined as: $work = rate \ *\ time$

where rate=amount of work that can be done in one unit of time

let a = rate of work A does in a day

let b = rate of work B does in a day

this means that: $10a + 10b=1$ where work=1 and it just means the entire job has been completed.

Since b can do it alone in 15 days, this means that: $15b=1$

If we divide by 15 here, we get the equation: $b=\frac{1}{15}$

We can now use this definition to substitute it into the first equation we made.

$10a + 10(\frac{1}{15}) = 1$

Multiply the 10 and 1/15

$10a+\frac{2}{3}=1$

subtract 2/3 from both sides

$10a=\frac{1}{3}$

Now divide both sides by 10

$a=\frac{1}{30}$

Now multiply this by 6, since we a represents the amount of work that can be done in a day, we want to find how many parts of the work can be done by a in 6 days

$6a=\frac{6}{30}$

Now divide both the numerator and denominator by 6

$a=\frac{1}{5}$

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2 years ago

What is the measurement of angle 2

AysviL [449]

69 is the measurement of angle 2

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2 years ago

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A quadrilateral is dilated by a scale factor of 2. It's original side measures are 7, 14, 21, and 28.

algol13

Answer:

14,28,42 and 56

Step-by-step explanation:

Multiply all lengths by 2 as the quadrilateral is dilated by a scale factor of 2

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3 years ago

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A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times.

tatyana61 [14]

Answer:

(a) $g(n)=0.05\cdot 2^n$

(b) $g^{-1}(n)=\log_{2}20g(n)$

(c)43 times

Step-by-step explanation:

<u>Part A</u>

The paper's thickness = 0.05mm

When the paper is folded, its width doubles (increases by 100%).

The thickness of the paper grows exponentially and can be modeled by the function:

$g(n)=0.05(1+100\%)^n\\\\g(n)=0.05\cdot 2^n$

<u>Part B</u>

<u /> $g(n)=0.05\cdot 2^n\\2^n=\dfrac{g(n)}{0.05}\\ 2^n=20g(n)\\$Changing to logarithm form, we have:\\\log_{2}20g(n)=n\\$Therefore:\\g^{-1}(n)=\log_{2}20g(n)$ <u />

<u />

<u>Part C</u>

If the thickness of the paper, g(n)=384,472,300,000 mm

Then:

$g^{-1}(n)=\log_{2}20g(n)\\g^{-1}(n)=\log_{2}20\times 384,472,300,000\\=\dfrac{\log 20\times 384,472,300,000}{\log 2} \\g^{-1}(n)=42.8 \approx 43\\n=43$

You must fold the paper 43 times to make the folded paper have a thickness that is the same as the distance from the earth to the moon.

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3 years ago