Answer:
64
Step-by-step explanation:
1
2
3
4
1, 2
1, 3
1, 4
2, 1
2, 3
2, 4
3, 1
3, 2
3, 4
4, 1
4, 2
4, 3
1, 2, 3
1, 2, 4
1, 3, 2
1, 3, 4
1, 4, 2
1, 4, 3
2, 1, 3
2, 1, 4
2, 3, 1
2, 3, 4
2, 4, 1
2, 4, 3
3, 1, 2
3, 1, 4
3, 2, 1
3, 2, 4
3, 4, 1
3, 4, 2
4, 1, 2
4, 1, 3
4, 2, 1
4, 2, 3
4, 3, 1
4, 3, 2
1, 2, 3, 4
1, 2, 4, 3
1, 3, 2, 4
1, 3, 4, 2
1, 4, 2, 3
1, 4, 3, 2
2, 1, 3, 4
2, 1, 4, 3
2, 3, 1, 4
2, 3, 4, 1
2, 4, 1, 3
2, 4, 3, 1
3, 1, 2, 4
3, 1, 4, 2
3, 2, 1, 4
3, 2, 4, 1
3, 4, 1, 2
3, 4, 2, 1
4, 1, 2, 3
4, 1, 3, 2
4, 2, 1, 3
4, 2, 3, 1
4, 3, 1, 2
4, 3, 2, 1
Ok
Probability (the point will be on unshaded part) = area of unshaded part / area of the circle.
= pi r^2 - s^2
-------------- where r = radius of circle and s = length of the side of the square.
pi r^2
-5y^2 + 2y + 2 = 0
y = -2 ± ✓4 - 4*-5*2. /. -10
y = -2 ± ✓44. / -10
y = -1 ± ✓11. / -5
(-1+✓11)/-5. and (-1-✓11)/-5
You are given a table in which each row represents the coordinates of points. For example, in the first line, we have x=-7 and y=5. Work through the four given equations, one at a time, subbing -7 for x and 5 for y; is the equation still true? If yes, then you have found the correct answer. B is the exception; I'd suggest you check out equations A, C and D first, before focusing on B.
Example: D: (5)-5 = 2((-7) + 7) leads to 0 = 0. Is that true? If so, D is likely the correct answer.
