The linear equation that has a slope of -7 and crosses the x-axis at (3, 0) is:
y = -7x + 21
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How to find the linear equation?</h3>
A general linear equation is:
y = a*x +b
Where a is the slope and b is the y-intercept.
The slope must be equal to the limit found in part a, and you say that it is equal to -7, so the slope is -7. And for how is written the problem, I understand that it crosses the x-axis at x = 3.
Then we will have:
y = -7*x + b
Such that, when x = 3, y = 0, then:
0 = -7*3 + b
21 = b
Then the linear equation is y = -7x + 21
If you want to learn more about linear equations:
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Answer:
Rational number as denominator is not equal to zero and numerator is a integer.
Answer: C. 0
Step-by-step explanation: 9+(-9) is the same thing as 9 - 9 which equals 0.
Since opposite angles are equal, 8x+12=5x+57. Subtracting 5x as well as 12 from both sides, we get 3x=45. . Dividing both sides by 3, we get x=15. Plugging x=15 into 5x+57, we get 5*15+57=75+57=132
The vertex of the parabola is (-3, 9)
In order to find the vertex of any quadratic, you start by finding the x-value of said vertex. This can be done using the equation below.
-b/2a
In this equation 'a' refers to the coefficient of x^2 (-1) and 'b' refers to the coefficient of x (-6). So then we can plug into that equation using those values.
-b/2a
-(-6)/2(-1)
6/-2
-3
Now that we have the x value, we can substitute that value into the equation to find the y value.
f(x) = -x^2 - 6x
f(x) = -(-3)^2 - 6(-3)
f(x) = -(9) + 18
f(x) = 9
Therefore our point is (-3, 9)