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3 years ago

6

The temperature outside dropped 13 degrees Fahrenheit in 7 hours. The final temperature was -2 degrees Fahrenheit. What was the

starting temperature? *

1 answer:

inysia [295]3 years ago

4 0

Answer:

Step-by-step explanation:

11 degrees. 13 + -2 = 11. The starting temperature was 11 degrees farenheit

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Which simplified fraction is equal to 0.53 repeating?

GalinKa [24]

Answer: I believe its 5/9

Step-by-step explanation:

As you can see, the only fraction that doesn't equal 0.53, or the outlier, is 5/9 or 0.5556

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Step-by-step explanation:

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3 years ago

Can someone help me solve this

Alex73 [517]

Domain: (-infinity,infinity)
Range: (-infinity,infinity)
as x goes to infinity y goes to: infinity
as x goes to -infinity y goes to: -infinity

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3 years ago

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Olin [163]

Answer:

Step-by-step explanation:

M' = (8,2)

A' = (7,6)

T' = (2,6)

H' =(3,2)

If this is a reflection across the y axis, then all that will change is the x value. You have to read that carefully to make sure you understand it.

Notice that T = (-2,6). All that happens is the the minus becomes a plus.

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3 years ago

Please for the love of god anwser my question lay correctly I really need your help :( I will give 25 points :)! This is geometr

tangare [24]

Answer:

$\displaystyle \rm A_{ \text{c - pentagon}} =41$

$\rm \displaystyle P _{ \rm c - pentagon} = 20+ 4 \sqrt{2}$

Step-by-step explanation:

we have a square and a triangle

we want to figure out the area and the perimeter of the pentagon

to figure out the area of the pentagon we can use the given formula:

$\displaystyle \rm A_{ \text{c - pentagon}} = A_{ \text{squre}} - A_{ \text{triangle}}$

let's figure out $A_{\rm square}$ :

since the given shape is a square Every angle of its 90° Thus the triangle is a right angle triangle

therefore the height is 4

$\displaystyle A _{ \rm triangle} = \frac{1}{2} \times b \times h$

substitute h and b

$\displaystyle A _{ \rm triangle} = \frac{1}{2} \times 4 \times 4$

reduce fraction:

$\displaystyle A _{ \rm triangle} = 2 \times 4$

simplify multiplication:

$\displaystyle A _{ \rm triangle} = 8$

likewise square

$\displaystyle A _{ \rm squre} = {s}^{2}$

substitute s:

$\displaystyle A _{ \rm squre} = {7}^{2}$

simplify square

$\displaystyle A _{ \rm squre} = 49$

hence,

$\displaystyle \rm A_{ \text{c - pentagon}} =49- 8$

$\displaystyle \rm A_{ \text{c - pentagon}} =41$

to figure out perimeter

let's figure out hypotenuse first

$\displaystyle h = \sqrt{ {4}^{2} + {4}^{2} }$

$\displaystyle h = \sqrt{ 16 + 16}$

$\displaystyle h = 4 \sqrt{2}$

therefore,

$\rm \displaystyle P _{ \rm c - pentagon} = 3 + 3 + 4 \sqrt{2} + 7 + 7$

$\rm \displaystyle P _{ \rm c - pentagon} = 6 + 4 \sqrt{2} + 14$

$\rm \displaystyle P _{ \rm c - pentagon} = 20+ 4 \sqrt{2}$

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3 years ago