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natulia [17]
3 years ago
14

I’m so lost please help fast

Mathematics
1 answer:
Romashka [77]3 years ago
3 0
Your screen is to blurry, can you redo the question?? I’d like to help.
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Plz help i know you are smart
stellarik [79]

Answer:

The numbers on the axis need to follow a repeating pattern

I think it's the last one coz in the graph, 50 jumps to 58 which breaks the repeating rule of 5

7 0
3 years ago
Can someone help me ​
AlladinOne [14]
No I’m sorry I am literally in 5th grade my guy
5 0
3 years ago
Read 2 more answers
△PQR is similar to △STU . In addition, m∠U=96° and m∠T=6(m∠P) . What is m∠P ? Enter your answer in the box. °
kenny6666 [7]
<span>△PQR is similar to △STU

</span>m∠R = m∠U = 96°

m∠Q = m∠T = 6

m∠P = 180 - ( 96 + 6)

m∠P = 180 - 102

m∠P = 78
 
answer 

m∠P = 78
7 0
4 years ago
Read 2 more answers
Please show working out thanks
IgorLugansk [536]

Answer:

10m x 15m

Step-by-step explanation:

You are given some information.

1. The area of the garden: A₁ = 150m²

2. The area of the path: A₂ = 186m²

3. The width of the path: 3m

If the garden has width w and length l, the area of the garden is:

(1) A₁ = l * w

The area of the path is given by:

(2) A₂ = 3l + 3l + 3w + 3w + 4*3*3 = 6l + 6w + 36

Multiplying (2) with l gives:

(3) A₂l = 6l² + 6lw + 36l

Replacing l*w in (3) with A₁ from (1):

(4) A₂l = 6l² + 6A₁ + 36l

Combining:

(5) 6l² + (36 - A₂)l +6A₁ = 0

Simplifying:

(6) l² - 25l + 150 = 0

This equation can be factored:

(7) (l - 10)*(l - 15) = 0

Solving for l we get 2 solutions:

l₁ = 10, l₂ = 15

Using (1) to find w:

w₁ = 15, w₂ = 10

The two solutions are equivalent. The garden has dimensions 10m and 15m.

3 0
3 years ago
Please do Correctly will mark you Brainliest!
ivolga24 [154]

Answer:

279...................................

4 0
3 years ago
Read 2 more answers
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