Answer:
f(n) = -11 + 22(n - 1)
<em>f(1) is your initial value.</em>
f(1) = -11 + 22(1 - 1)
f(1) = -11
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f(2) = -11 + 22(2 - 1) = 11
f(3) = -11 + 22(3 - 1) = 33
f(4) = -11 + 22(4 - 1) = 55
<em>f(n - 1) is just a notation for the previous term</em>
<em>Using the equation f(n) = f(n - 1) + _______ :</em>
f(2) = f(1) + ??? = 11
f(3) = f(2) + ??? = 33
f(4) = f(3) + ??? = 55
f(2) = -11 + ??? = 11
f(3) = 11 + ??? = 33
f(4) = 33 + ??? = 55
f(2) = -11 + 22 = 11
f(3) = 11 + 22 = 33
f(4) = 33 + 22 = 55
∴ f(n) = f(n - 1) + 22
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Good luck on this it's pretty easy
All your doing here is 37-19 adding negative is the same has munising
So 37-19=18
Answer: 81 cookies per tray
Step-by-step explanation:
567/7= 81
