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nevsk [136]
4 years ago
14

Chase has been playing a game where he can create towns and help his empire expand. Each town he has allows him to create 1.13 t

imes as many villagers. The game gave Chase four villagers to start with. Help Chase expand his empire by solving for how many villagers he can create with 17 towns. Then explain to Chase how to create an equation to predict the number of villagers for any number of towns. Show your work and use complete sentences.
Mathematics
1 answer:
riadik2000 [5.3K]4 years ago
7 0

Well the way I see it is he started with 4 villager so I would see the equation to be

 1.13x times 17+4 would equal the amount of villagers he could have which would be 23.21 as for the equation it would be 1.13x times 17 plus four equals the number of villagers total

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It has been observed that, during various forms of social competition, men experience an increase in testosterone levels. A 2018
svetoff [14.1K]

Answer:

= ( -4.725, 6.945) pg/ml

Therefore at 95% confidence interval (a,b) = ( -4.725, 6.945) pg/ml

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean gain x = 1.11 pg/ml

Standard deviation r = 15.18 pg/ml

Number of samples n = 26

Confidence interval = 95%

z(at 95% confidence) = 1.96

Substituting the values we have;

1.11+/-1.96(15.18/√26)

1.11+/-1.96(2.977042931397)

1.11+/-5.835004145539

1.11+/-5.835

= ( -4.725, 6.945) pg/ml

Therefore at 95% confidence interval (a,b) = ( -4.725, 6.945) pg/ml

7 0
3 years ago
In a survey, 28 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped
Rina8888 [55]

Answer:

The 80% confidence level estimate for how much a typical parent would spend on their child's birthday gift is between $33.954 and $35.246.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution should be used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 28 - 1 = 27

80% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 27 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.8}{2} = 0.9. So we have T = 1.314

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.314\frac{2.6}{\sqrt{28}} = 0.646

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 34.6 - 0.646 = $33.954

The upper end of the interval is the sample mean added to M. So it is 34.6 + 0.646 = $35.246

The 80% confidence level estimate for how much a typical parent would spend on their child's birthday gift is between $33.954 and $35.246.

3 0
3 years ago
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Vaselesa [24]

9514 1404 393

Answer:

  1. B, E

  2. A, E

  16. B'(1, 5)

Step-by-step explanation:

Lines p and r are parallel, as are lines a and b. Either of the lines in one parallel pair is perpendicular to the lines in the other parallel pair. Line q has no necessary relation to anything, so can be ignored. (No answer containing q can be correct.)

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1.  p ⊥ b

  r ⊥ a

__

2.  r║p

  a║b

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16. Point B(3, 2) translated (right, up) = (-2, 3) will be ...

  B' = B + (-2, 3) = (3, 2) +(-2, 3) = (3 -2, 2 +3)

  B' = (1, 5)

Note: (x, y) coordinates are (<em>right</em>, <em>up</em>). So, in translation problems it is important to <em>pay attention.</em> Often, the up/down translation is listed before the left/right translation. If you're not paying attention, you may inadvertently reverse the numbers that need to be added to the coordinates to do the translation.

5 0
3 years ago
Suppose A,B and C are 2 ×2 matrices , E,F and G are 3 × 3 matrices, H and K are 2×3 matrices and L and M are 3×2 matrices. For e
Alekssandra [29.7K]

Answer:

a) 2x2 b)3x3 c) Not possible d) 2x3 e) 3x2 f) 3x3 g)Not possible h)3x2

Step-by-step explanation:

-> we can only add matrices with same size

-> we can only multiply when columns of first equal to rows of second

-> nxm multiplied by pxq gives nxq eg 3x2 mul 2x2 gives 3x2

-> addition and mul by const number dont change the size

So considering the above facts :-

a) AB+C = [(2x2)(2X2)]+(2x2)=(2x2)+(2x2)=2x2

b) 3GF =3[(3x3)(3x3)]=3(3x3)=3x3

c)CK+B= [(2x2)(2x3)]+(2x2)=(2x3)+(2x2) which is not possible (see point 1)

d)CK+H =as CK is (2x3) so (2x3)+(2x3)=(2x3)

e)EMC=[(3x3)(3x2)](2x2)=(3x2)(2x2)=3x3

f)GLH=[(3x3)(3x2)](2x3)=(3x2)(2x3)=3x3

g)HLG=[(2x3)(3x2)](3x3)=(2x2)(3x3)= not possible(see point 2)

h)2EL+5MB=2[(3x3)(3x2)]+5[(3x2)(2x2)]=(3x2)+(3x2)=3x2

   

8 0
3 years ago
Convert this to a decimal then a percent
Ahat [919]
9/27=33.3% repeating 3 = 0.3 repeating 3

18/27= 66.6 repeating 6 = 0.6 repeating 6
4 0
4 years ago
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