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DiKsa [7]
3 years ago
5

Pyramid A is a square pyramid with a base side length of 14 inches and a height of 6 inches. Pyramid B has a volume of 3,136 cub

ic inches. How many times bigger is the volume of pyramid B than pyramid A? Give your answer as a percentage. Provide an explanation and proof for your answer to receive full credit.
Mathematics
2 answers:
leonid [27]3 years ago
8 0

The Volume of PYRAMID A is 8 times greater than the Volume of PYRAMID B as obtained by taking the ratio of the volume of both pyramids.

Volume of a square based pyramid is given as :

V = a^2h/3

Where; h = height ; a = base edge

Hence, Volume of PYRAMID A :

V = 14^2 * (6/3)\\\\V = 392 in^3

Volume of PYRAMID B = 3,136 in³

Divide Volume of pyramid B by pyramid A :

3136 in^3 / 392 in^3

= 8 times

Expressing as a percentage, multiply by 100% ;

8 * 100% = 800%

Therefore, The volume of PYRAMID B is 800% times GREATER THAN that of PYRAMID A.

Learn more :

brainly.com/question/17615619

Alisiya [41]3 years ago
6 0

Answer:

r = 8  ( The volume of pyramid B is 8 times bigger than the volume of pyramid A

As percentage

The volume of pyramid B is 800 % bigger than the volume of pyramid A

Step-by-step explanation:

The volume for a right square pyramid is:

V = (1/3) * x²*h        where  x is the side of the square base and h the height, according to this: the volume of pyramid A is:

V(A) = (1/3)* (14)²*6 = 392 in³

Pyramid B has a volume of  3136 in³.

For us to get how many times the volume of pyramid B is bigger than the volume of pyramid A, we divide

r = Volume of pyramid B / Volume of pyramid A

r = 3136/ 392

r = 8

As percentage volume of pyramid B is 800 % bigger than the volume of pyramid A

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Answer:

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b) 117.9

c) Option A)  When there is rounding or grouping, the median can be highly sensitive to small change

Step-by-step explanation:

We are given the following data set in the question:

108.6, 117.4, 128.4, 120.0, 103.7, 112.0, 98.3, 121.5, 123.2

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}

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Median =

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b) New median of the reported values

Data: 108.6, 117.9, 128.4, 120.0, 103.7, 112.0, 98.3, 121.5, 123.2

Sorted Values: 98.3, 103.7, 108.6, 112.0, 117.9, 120.0, 121.5, 123.2, 128.4

New Median =

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c) Since median is a position based descriptive statistics, a small change in values can bring a change in the median value as the order of the data may change.

Option A)  When there is rounding or grouping, the median can be highly sensitive to small change

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10*3 tens= 30= 300 units
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