the answer is 0 a 90° counterclockwise rotation because i know and think that is the answer
<span>The number of cell phone minutes used by high school seniors follows a normal distribution with a mean of 500 and a standard deviation of 50. what is the probability that a student uses more than 580 minutes?
Given
μ=500
σ=50
X=580
P(x<X)=Z((580-500)/50)=Z(1.6)=0.9452
=>
P(x>X)=1-P(x<X)=1-0.9452=0.0548=5.48%
</span>
X f πxf
-1 2 -2
3 1 3
-1 -2 2
0 -3 0
total =3
mean (π)=πxf ÷n
= 3÷4
= 0.75 these is not answer I thank so
