Answer:
a. p(orange) = 5/14
b. p(green) = 3/14
c. p(red) = 1/7
d. p(brown) = 2/7
e. p(brown or red) = 3/7
Step-by-step explanation:
1. You have a 14 pencils. Two pencils are red, 5 pencils are orange, 3 pencils are green and 4 pencils are brown.
p(color) = (number of pencils of that color)/(total number of pencils)
p(color) = (number of pencils of that color)/14
a. If a pencil is picked at random, what is the probability that the pencil
will be orange?
p(orange) = 5/14
b. If a pencil is picked at random, what is the probability that the pencil
will be green?
p(green) = 3/14
c. If a pencil is picked at random, what is the probability that the pencil will be red?
p(red) = 2/14 = 1/7
d. If a pencil is picked at random, what is the probability that the pencil
will be brown?
p(brown) = 4/14 = 2/7
e. If a pencil is picked at random, what is the probability that the pencil
will be brown or red?
brown: 4
red: 2
brown or red: 4 + 2
p(brown or red) = 6/14 = 3/7
Answer:
6xy(15xy−1)
Step-by-step explanation:
Perpendicular has the reciprocal slope and u have to put the point given into point slope.
y-3=9/2(x-4)
(The slope of the original equation was -2/9)
Here's one way to do it.
AB ≅ AC . . . . . . . . . . given
∠BAY ≅ ∠CAY . . . . given
AY ≅ AY . . . . . . . . . . reflexive property
ΔBAY ≅ ΔCAY . . . .. SAS congruence
XY ≅ XY . . . . . . . . . . reflexive property
∠AYB ≅ ∠AYC . . . . CPCTC
BY ≅ CY . . . . . . . . . . CPCTC
ΔXYB ≅ ΔXYC . . . .. SAS congruence
Therefore ...
∠XCY ≅ ∠XBY . . . . CPCTC
I uploaded it here as the answers Bc
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