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2 years ago

A no correlation b positive c quadratic correlation d negative

Mathematics

1 answer:

musickatia [10]2 years ago

4 0

because it is in the negative plan of the graph

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A movie theater manager of a small theater sells two sizes of popcorn at the concession stand. A jumbo popcorn has a profit of $

NeX [460]

j4 + m3 = p

If you multiply j, which is the number of jumbo popcorns sold by its price, you are given the profit of the Jumbo boxes for a single day. If you multiply m, which is the number of mini popcorns sold by its price, you are given the profit of the Mini boxes for a single day. If you add the profits from both boxes together... you are given p, which is the total profit for the day.

5 0

1 year ago

Which statements are true about the linear inequality y > 3/4x – 2?

skad [1K]

The slope of the line is .75, so 1. is false.

The graph is a dashed line AND the area above it shaded, so 2. is false (in and of itself)

The graph is the area shaded above the line not below it, so 3. is false.

0>.75(0)-2, 0>-2 so 4. is TRUE

The line is dashed and is not part of the solution to the inequality, so the point (0,-2) while on the line, is not part of the solution set and thus is not part of the graph, and does not intercept the graph, so 5. false. (the line intercepts the y axis at (0, -2) but the line itself is not part of the solution set and thus is not part of the graph)

So only statement 4. is true.

7 0

2 years ago

Ak = v+w solve for a

pav-90 [236]

Answer:

a= v+w-k

Step-by-step explanation:

Get 'a' by itself to make it a solvable equation

so, subtract k from both sides so it can cancel itself on the 'a' side

7 0

2 years ago

Read 2 more answers

Given: △ABC, m∠A=60°

Anon25 [30]

Answer:

Perimeter = 32.3

Area = 95.24

Step-by-step explanation:

Given:

△ABC, m∠A=60°

m∠C=45°, AB = 9

To find:

Perimeter of △ABC

Area of △ABC

Solution:

Using angle sum property in a triangle:

m∠A + m∠B + m∠C = 180°

m∠B = 180° - 45° - 60° = 75°

As per Sine Rule:

$\dfrac{a}{sinA} = \dfrac{b}{sinB} = \dfrac{c}{sinC}$

Where

$a$ is the side opposite to $\angle A$

$b$ is the side opposite to $\angle B$

$c$ is the side opposite to $\angle C$

$\dfrac{BC}{sin60^\circ} = \dfrac{AC}{sin 75^\circ} = \dfrac{AB}{sin 45^\circ} \\\Rightarrow \dfrac{BC}{\frac{\sqrt3}{2}} = \dfrac{9}{\frac{1}{\sqrt2}} \\\Rightarrow BC = 12.73\times 0.87 \\\Rightarrow BC = 11.08$

$\Rightarrow \dfrac{AC}{0.96} = \dfrac{9}{\frac{1}{\sqrt2}} \\\Rightarrow AC = 12.73\times 0.96 \\\Rightarrow AC = 12.22$

Perimeter of △ABC = AB + BC + AC = 9 + 11.08 + 12.22 = <em>32.3</em>

Area of a triangle is given as:

$\dfrac{1}2\times ab sin(angle\ between\ a\ and\ b)$

$\Rightarrow \dfrac{1}{2}\times AB\times AC\times sinA\\\Rightarrow 9\times 12.22\times sin 60\\\Rightarrow \bold{95.24}$

8 0

2 years ago

Find a number C such that the polynomial p(x)= -x+4x^2+Cx^3-8x^4

Ksenya-84 [330]

Answer:

C = 2

Step-by-step explanation:

$p(x)= -x+4x^2+Cx^3-8x^4 \\ \\ \because \: given \: polynmial \: has \: zero \: at \: \\x = \frac{1}{4} \\ \\ \implies \: p\bigg(\frac{1}{4} \bigg) = 0...(1) \\ \\ plug \: x = \frac{1}{4} \: in \: p(x) \: we \: find \\ \\ p \bigg(\frac{1}{4} \bigg) = - \frac{1}{4} + 4 {\bigg(\frac{1}{4} \bigg)}^{2} + c {\bigg(\frac{1}{4} \bigg)}^{3} - 8 {\bigg(\frac{1}{4} \bigg)}^{4} \\ \\ 0 = - \frac{1}{4} + \cancel 4 \times {\frac{1}{\cancel{16} } } + c {\bigg(\frac{1}{64} \bigg)} - \cancel 8 \times \frac{1}{\cancel{256} } \\ \\0 =\cancel{ - \frac{1}{4}} + \cancel {{\frac{1}{4} }} + c {\bigg(\frac{1}{64} \bigg)} - \times \frac{1}{32} \\ \\0 = c {\bigg(\frac{1}{64} \bigg)} - \frac{1}{32} \\ \\c {\bigg(\frac{1}{64} \bigg)} = \frac{1}{32} \\ \\ c = \frac{1}{32} \times 64 \\ \\ c = 2$

5 0

2 years ago