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3 years ago

Si el divisor es 9 el cociente es 35 y el residuo 4 ¿ cuál es el dividendo?

Mathematics

1 answer:

nordsb [41]3 years ago

3 0

Answer:

319

Step-by-step explanation:

Dividendo = divisor × cociente + residuo

Espero que esto ayude

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What is the coordinate f G if triangle E F G is created by dilating EFG with a scale factor of 4 about the origin?

garri49 [273]

Answer:

Segment EH and segment E prime H prime both pass through the center of dilation (A)

The complete question related to this found on brainly (ID:16812154) is stated below:

Triangle EFG is dilated by a scale factor of 3 centered at (0, 1) to create triangle E'F'G'. Which statement is true about the dilation?

E(0,5) F(1,1) G(-2,1) H(0,1)

a) segment EH and segment E prime H prime both pass through the center of dilation.

b)The slope of segment EF is the same as the slope of segment E prime H prime.

c) segment E prime G prime will overlap segment EG. segment

d) EH ≅ segment E prime H prime.

Step-by-step explanation:

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3 years ago

What's the constant of proportionality in the equation d=70t

xenn [34]

Answer:

The constant of proportionality is 70.

Step-by-step explanation:

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4 years ago

Can someone help me with this

timurjin [86]

200 is the answer sir

8 0

3 years ago

Graph the system of inequalities presented here on your own paper, then use your graph to answer the following questions: y <

levacccp [35]

Solution-

The given inequalities are,

$y < 2x-7,\\\\y\geq-\frac{1}{2}x+3$

Part A

As the former inequality is only '<' so it will be represented as dotted line, but in case of the later inequality there is '≥' so it will be represented as a solid line.

This happens because in only '<, >' the values must be either lesser or greater than y, they can't take the values of y, but in case of '≤, ≥' the values can be equal to y.

Taking origin (0, 0) and putting in the first inequality.

$\Rightarrow 0< 2(0)-7\\\\\Rightarrow 0\nless -7$

As the equation does not satisfy, so the shaded area will be on the other side of the origin.

Again taking origin (0, 0) and putting in the second inequality.

$\Rightarrow 0\geq-\frac{1}{2}0+3\\\\\Rightarrow 0\ngeqslant 3$

As the equation does not satisfy, so the shaded area will be on the other side of the origin.

The second attachment contains the feasible region.

Part B

In order to know whether the point (3, −7) is included in the solution area for the system or not, we must put it in both the equations, if it satisfies both then only it is within the solution area.

$\Rightarrow -7< 2(3)-7,\ -7\geq-\frac{1}{2}(3)+3\\\\\Rightarrow -7$

As the point (3, -7) only satisfies first inequality, but not the second inequality so this point won't be in the solution area.

6 0

3 years ago

Read 2 more answers

Please help: 12x^4(-5/6x^3y^2) If possible, include steps Thanks.

tangare [24]

---------------------------------------------------------------------------------------
Question
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$12x^4(- \frac{5}{6} x^3y^2)$

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Multiply the constant: 12 x (-5/6)
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$-10x^4( x^3y^2)$

---------------------------------------------------------------------------------------
Multiply the x (we add the power together when we multiply)
---------------------------------------------------------------------------------------
$-10x^7y^2$

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Answer: -10x⁷y²
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3 years ago