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Nimfa-mama [501]
3 years ago
8

Which is equivalent to x3y–7? x cubed y Superscript 7 StartFraction x cubed Over y Superscript 7 EndFraction StartFraction x cub

ed Over y Superscript negative 7 EndFraction StartFraction y Superscript 7 Over x cubed EndFraction
Mathematics
1 answer:
butalik [34]3 years ago
4 0

Answer:

x^3y^{-7} =  \frac{x^3}{y^7}

Step-by-step explanation:

Given

x^3y^{-7}

Required

The equivalent

We have:

x^3y^{-7}

Apply the following rule of exponents

a^{-b} = \frac{1}{a^b}

So, we have:

x^3y^{-7} = x^3 * \frac{1}{y^7}

x^3y^{-7} =  \frac{x^3}{y^7}

You might be interested in
According to a study done by the Gallup organization, the proportion of Americans who are satisfied with the way things are goin
UkoKoshka [18]

Answer:

21.77% probability that the proportion who are satisfied with the way that things are going in their life exceeds 0.85

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

For proportions p in a sample of size n, we have that \mu = p, \sigma = \sqrt{\frac{p(1 - p)}{n}}

In this problem:

\mu = 0.82, \sigma = \sqrt{\frac{0.82*0.18}{100}} = 0.0394

In a sample of 100 Americans, what is the probability that the proportion who are satisfied with the way that things are going in their life exceeds 0.85

This is 1 subtracted by the pvalue of Z when X = 0.85. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.85 - 0.82}{0.0384}

Z = 0.78

Z = 0.78 has a pvalue of 0.7823

1 - 0.7823 = 0.2177

21.77% probability that the proportion who are satisfied with the way that things are going in their life exceeds 0.85

5 0
3 years ago
HELP ASAP PLEASE!!!!!!!!!!!!!!!
TiliK225 [7]
ITS D!! It’s the third option !!
8 0
3 years ago
A cell phone company charges a monthly fee plus $0.25 for each text message. The monthly fee is $30.00 and you owe $59.50. Write
Vaselesa [24]
The equation is at the top, the steps are in between, and the answer is at the bottom
hope this helps

6 0
3 years ago
Two airplanes leave an airport at the same time, the first headed due north and the second at a bearing of N42^ E . At 2:00PM, t
Leno4ka [110]

Answer:

The two airplanes are about 330miles apart.

Step-by-step explanation:

The diagram interpreting the question has been attached to this response.

As shown in the diagram,

i. the airplanes leave at point C.

ii. at 2.00pm the first and second airplanes are at points A and B respectively, where they are 312miles and 487miles away from the starting point C in directions due north and N42E from the point C.

iii. the points A, B and C form a triangle with sides a, b and c.

To solve for the value of c which is the distance between the two planes at 2.00pm, the cosine rule is used.

c² = a² + b² - 2abcosC            --------------(i)

where;

b  = 312miles

a = 487miles

C = 42°

Substitute these values into equation (i) and solve as follows;

c² = (487)² + (312)² - 2(312)(487)cos(42)

c² = (237169) + (97344) - 303888cos(42)

c² = (237169) + (97344) - 303888(0.7431)

c² = 334513 - 225819.1728

c² = 108693.8272

<em>Take the square root of both sides</em>

√c² = √108693.8272

c = 329.69

c ≅ 330miles

Therefore, the two airplanes are far apart by 330miles

3 0
2 years ago
Mathematics.................
Sergeu [11.5K]

Answer:

this Is 3 and the second one is also 3

8 0
2 years ago
Read 2 more answers
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