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DerKrebs [107]
3 years ago
5

Samuel deposited money in an account that pays an annual simple interest rate of 3.5%. at the end of 5 years, samuel earns $2625

.00 in interest. how much money had he deposited in the account?
Mathematics
2 answers:
evablogger [386]3 years ago
4 0
He has deposited 1500 dollars into the account.
bezimeni [28]3 years ago
3 0
P=i/rt
P=2625/0.035*5
P==15,000
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Answer:

3n+10

Step-by-step explanation:

6(n+4)-4

PEMDAS

start with parenthesizes

6 x n = 6n

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Why are quartiles generally more reliable for judging outliers than mean and standard deviation?
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What is the slope of a line between (-4,14) and (-16,8)
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\frac{1}{2}

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Round 76 to the nearest tenth
Elden [556K]
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The next smaller tenth is  75.9 .

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76 is already rounded to the nearest tenth.
8 0
3 years ago
Read 2 more answers
Suppose that a local TV station conducts a survey of a random sample of 120 registered voters in order to predict the winner of
forsale [732]

Answer:

a) The 99% CI for the true proportion of voters who prefer the Republican candidate is (0.3658, 0.6001). This means that we are 99% sure that the true population proportion of all voters who prefer the Republican candidate is (0.3658, 0.6001).

b) The upper bound of the confidence interval is above 0.5 = 50%, which meas that the candidate can be confidence of victory.

Step-by-step explanation:

Question a:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

Sample of 120 registered voters in order to predict the winner of a local election. The Democrat candidate was favored by 62 of the respondents.

So 120 - 62 = 58 favored the Republican candidate, so:

n = 120, \pi = \frac{58}{120} = 0.4833

99% confidence level

So \alpha = 0.01, z is the value of Z that has a p-value of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.  

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4833 - 2.575\sqrt{\frac{0.4833*0.5167}{120}} = 0.3658

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4833 + 2.575\sqrt{\frac{0.4833*0.5167}{120}} = 0.6001

The 99% CI for the true proportion of voters who prefer the Republican candidate is (0.3658, 0.6001). This means that we are 99% sure that the true population proportion of all voters who prefer the Republican candidate is (0.3658, 0.6001).

b. If a candidate needs a simple majority of the votes to win the election, can the Republican candidate be confident of victory? Justify your response with an appropriate statistical argument.

The upper bound of the confidence interval is above 0.5 = 50%, which meas that the candidate can be confidence of victory.

8 0
3 years ago
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