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2 years ago

Question 8 of 10 What is the median of this data set? 14, 18, 31, 34, 44, 50 A. 32.5 B. 33 C. 31.5 O O D. 31 SUBM

Mathematics

2 answers:

kozerog [31]2 years ago

8 0

Answer:

32.5

Step-by-step explanation:

median is the middle number, in this case the sum of the two middle number divided by 2

31 + 34 = 65/2

32.5

andreyandreev [35.5K]2 years ago

4 0

Answer:

Step-by-step explanation:

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TV and YW are parallel lines.

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Step-by-step explanation:

A is incorrect because TUX and VUS are vertical angles.

B is incorrect because YXZ and TUX have no relationship.

C is correct because WXZ and WXU are supplementary angles, thus adjacent.

D is inccorect because VUX and TUS are vertical angles.

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2 years ago

In a racing game, Austin has traveled 1,988 meters from the starting line. He's cruising with confidence when suddenly he slips

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2 years ago

If I have 11 hours to do three things, how much time do I have to do each thing?

kogti [31]

11 hours = 3
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2 years ago

Read 2 more answers

Six items purchased at a grocery store weigh 11 kilograms one of the items is detergent weighing 556 grams what is the total wei

slavikrds [6]

$556 \: g \times \frac{1 \: kg}{1000g} = 0.556 \: kg$

$11 \: kg - 0.556 \: kg = 10.444 \: kg$

The total weight of the other five items are 10.444 kg

<em>(round as you wish)</em>

7 0

2 years ago

Find the sum of the geometric series 512+256+ . . .+4

mario62 [17]

$\bf 512~~,~~\stackrel{512\cdot \frac{1}{2}}{256}~~,~~...4$

so, as you can see above, the common ratio r = 1/2, now, what term is +4 anyway?

$\bf n^{th}\textit{ term of a geometric sequence}\\\\a_n=a_1\cdot r^{n-1}\qquad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\r=\frac{1}{2}\\a_1=512\\a_n=+4\end{cases}$

$\bf 4=512\left( \cfrac{1}{2} \right)^{n-1}\implies \cfrac{4}{512}=\left( \cfrac{1}{2} \right)^{n-1}\\\\\\\cfrac{1}{128}=\left( \cfrac{1}{2} \right)^{n-1}\implies \cfrac{1}{2^7}=\left( \cfrac{1}{2} \right)^{n-1}\implies 2^{-7}=\left( 2^{-1}\right)^{n-1}\\\\\\(2^{-1})^7=(2^{-1})^{n-1}\implies 7=n-1\implies \boxed{8=n}$

so is the 8th term, then, let's find the Sum of the first 8 terms.

$\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\r=\frac{1}{2}\\a_1=512\\n=8\end{cases}$

$\bf S_8=512\left[ \cfrac{1-\left( \frac{1}{2} \right)^8}{1-\frac{1}{2}} \right]\implies S_8=512\left(\cfrac{1-\frac{1}{256}}{\frac{1}{2}} \right)\implies S_8=512\left(\cfrac{\frac{255}{256}}{\frac{1}{2}} \right)\\\\\\S_8=512\cdot \cfrac{255}{128}\implies S_8=1020$

7 0

3 years ago

Question 8 of 10 What is the median of this data set? 14, 18, 31, 34, 44, 50 A. 32.5 B. 33 C. 31.5 O O D. 31 SUBM​

Question 8 of 10 What is the median of this data set? 14, 18, 31, 34, 44, 50 A. 32.5 B. 33 C. 31.5 O O D. 31 SUBM