Write an equation in point-slope form of the line with slope –8 that contains the point j(–3, 2).
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Answer:
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<span>y=-3x²-30x-27
Δ=b²-4ac=(-30)²-4.(-3).(-27)=900-324=576 ∴ √Δ=24
x'=(-b
√Δ)/2a=(-(-30)24)/2.(-3)=-54/6=-9
x''=</span><span>(-b-√Δ)/2a=(-(-30)-24)/2.(-3)=-6/6=-1
Raízes são x''=-9 e x''=-1
</span>
Δ=b²-4ac=(-30)²-4.(-3).(-27)=900-324=576 ∴ √Δ=24
x'=(-b
x''=</span><span>(-b-√Δ)/2a=(-(-30)-24)/2.(-3)=-6/6=-1
Raízes são x''=-9 e x''=-1
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