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Nina [5.8K]
3 years ago
7

There is a bag filled with 4 blue, 3 red and 5 green marbles.

Mathematics
1 answer:
spayn [35]3 years ago
8 0

Answer:

fgjookbfdsx njjoplnnnvfdsaazcv bhhukl

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What is the measure for
Gemiola [76]

Answer:

66

Step-by-step explanation:

Since it's a 90 degree angle.

90-24=66

4 0
3 years ago
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Find the width of a rectangular patio with a length of 16 feet and an area of 200 square feet
beks73 [17]

Answer:

Step-by-step explanation:

You already know the area, so just reverse the steps. Example: 200ft divided by the length which is 16ft equals 12.5 feet

4 0
4 years ago
Last trig question!! Please explain how to do this!! Thank youuu !!!!!!
Shalnov [3]

Answer:

See the verification below.

Step-by-step explanation:

Starting expression: sin^3(x)+sin(x)\,cos^2(x)=sin(x)

Extract from the expression on the left of the equal sign the common factor "sin(x)":

sin^3(x)+sin(x)\,cos^2(x)=sin(x)\\sin(x)[sin^2(x)+cos^2(x)]=sin(x)

Now use the Pythagorean trigonometric identity: sin^2(x)+cos^2(x)=1 to replace the expression in between square brackets with "1":

sin(x)[sin^2(x)+cos^2(x)]=sin(x)\\sin(x) \,[1]=sin(x)\\sin(x)=sin(x)

Therefore we have verified the identity

7 0
3 years ago
Bryan owns a pet store. He puts one parrot in per cage, he has one parrot extra. If he puts two parrots per cage, he has a cage
Ilya [14]

Answer:

4 parrots

3 cages

Step-by-step explanation:

Bryan has one more parrot than cages and one more cage than half the number of parrots. The following system of equations can be modeled for the number of parrots (P) and cages (C):

P=C+1\\C-1=\frac{P}{2}

Solving the linear system:

P-1-1=\frac{P}{2}\\0.5P = 2\\P=4\\C=P-1=4-1=3

Bryan has 4 parrots and 3 cages.

6 0
3 years ago
Car dealerships claim to make most of their money from servicing cars. In a certain month, an Acura dealership sold fifteen less
MA_775_DIABLO [31]

Answer:

New cars sold = 20,

Used cars sold = 25

Cars serviced = 290

Step-by-step explanation:

In a month they sold fifteen less used cars than twice the number of new cars.

Lets say 'x' number of new cars were sold, then:

The number of used car sold is:

2\times x-15=2x-15

In the same month they serviced fifty more than twelve times the number of new cars sold. So the number of cars serviced is:

12\times x+50=12x+50

Altogether they sold or serviced 335 cars, so the sum of all the cars sold and serviced should be 335:

x+(2x-15)+(12x+15)=335

Solving for 'x' we get:

x+2x+12x-15+50=335

15x+35=335

15x=335-35=300

x=\frac{300}{15}=20

Therefore, the number of new cars sold in that month is 20.

Number of used car sold =2x-15=2\times 20-15=40-15=25

Number of cars serviced =12\times x+50=12\times20+50=240+50=290

We can also cross check by summing them up:

290+25+20=335

8 0
3 years ago
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