Answer:
There is a bag filled with 4 blue, 3 red and 5 green marbles.
1 answer:
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We are given these three people age below:
- Jim's age
- Carla's age
- Tomy's age
We define the age of Jim as any variable, because the problem doesn't give any specific age. I will define Jim's age as x.
- Jim's age = x
Next, Carla is 5 years older than Jim. That means if Carla is 5 years older, her age would be x+5.
- Carla's age = x+5
Then Tomy is 6 years older than Carla. That means the age would be 6+(x+5).
- Tomy's age = 6+(x+5)
The sum of their three ages is 31 years old. That means we add all these ages and equal to 31.
Combine like terms and solve for x.
Then we substitute the value of x in ages to find these three people ages.
- Jim's age = x = 5
- Carla's age = x+5 = 5+5 = 10
- Tomy's age = 6+(x+5) = 6+(5+5) = 6+10 = 16.
Answer
- Jim's age = 5
- Carla's age = 10
- Tomy's age = 16
Answer: AAA similarity.
Step-by-step explanation: CB is the transversal for the parallel lines AB and DE, and so by transverse property, we have ∠CED ≅ ∠CBA. Similarly, CA acts as a tranversal for the same pair of parallel lines AB and DE and using the same property, we can have ∠CDE ≅ ∠CAB. Now, in triangles CED and ABC, we have
∠CED ≅ ∠CBA,
∠CDE ≅ ∠CAB
and
∠DCE ≅ ∠ACB [same angle]
Hence, by AAA (angle-angle-angle) similarity,
△CED ~ △ABC.
Thus, the correct option is AAA similarity.
