Answer:
<h2>C. <em>
20,160</em></h2>
Step-by-step explanation:
This question bothers on permutation since we are to select a some people out of a group of people and then arrange in a straight line. If r object are to be arranged in a straight line when selecting them from n pool of objects. This can be done in nPr number of ways.
nPr = n!/(n-r)!
Selection of 6 people out of 8 people can therefore be done in 8C6 number of ways.
8P6 = 8!/(8-6)!
8P6 = 8!/2!
8P6 = 8*7*6*5*4*3*2!/2!
8P6 = 8*7*6*5*4*3
8P6 = 56*360
8P6 = 20,160
<em>Hence this can be done in 20,160 number of ways</em>
Answer:
57
Step-by-step explanation:
Angle IHK and JKH are alternate angles.
Alternate angles are equal
What you do is plug the z value (first column) into the formula (second column), and solve for y. For instance, the first one would be y = -1-2, or -3. The x would be the x in the ordered pair, and the final ordered pair would be (-1,-3). Make sense?
The equation of a line starting from two points is:

From the first point you get: x1 = -1, y1 = -2
From the second point you get: x2 = 3, y2 = 10
Replace x1, y1, x2, y2 in the equation of the line and you get:



From this you get the equation of your line: