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Gekata [30.6K]
2 years ago
12

Mr. And Mrs. Griffin hope to send their daughter to college in fourteen years. How much money should they invest now at an inter

est rate of 9.5% per year, compounded continuously, in order to be able to contribute $8,500 to her education?
Mathematics
1 answer:
goldfiish [28.3K]2 years ago
4 0

Answer:

$2,385.75 = P

Step-by-step explanation:

In order to calculate this we need to use the following compound interest formula and solve for the initial investment amount which is P.

A = P (1 + r/n) (nt)

A = the future value of the investment/loan, including interest

P = the principal investment amount (the initial deposit or loan amount)

r = the annual interest rate (decimal)

n = the number of times that interest is compounded per unit t

t = the time the money is invested or borrowed for

If we plug in the values provided in the question which is compounded once per year we would get the following equation which we can solve for P.

8500 = P (1 + (0.095/1))^(1*14)

8500 = P (1.095)^(14)

8500 = P (3.56285)

2,385.75 = P

Mr. and Mrs. Griffen need to invest $2,385.75 now for 14 years in order to contribute a total of $8,500

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Your balance would be 35, I think
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3 years ago
An NBA fan named Mark claims that there are more fouls called on his team 1 point
inn [45]

Answer:

t=\frac{12.2-11.5}{\frac{1.6}{\sqrt{34}}}=2.551    

df = n-1=34-1=33

p_v =P(t_{(33)}>2.551)=0.008  

Since the p value is less than the significance level of 0.05 we have enough evidence to reject the null hypothesis in favor of the claim

And the best conclusion for this case would be:

b)The p-value is 0.008, indicating sufficient evidence for his claim.

Step-by-step explanation:

Information provided

\bar X=12.2 represent the sample mean fould against

s=1.6 represent the sample standard deviation

n=34 sample size  

represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean is higher than 11.5 fouls per game:  

Null hypothesis:\mu \leq 11.5  

Alternative hypothesis:\mu > 11.5  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

The statistic is given by:

t=\frac{12.2-11.5}{\frac{1.6}{\sqrt{34}}}=2.551    

P value

The degreed of freedom are given by:

df = n-1=34-1=33

Since is a one side test the p value would be:  

p_v =P(t_{(33)}>2.551)=0.008  

Since the p value is less than the significance level of 0.05 we have enough evidence to reject the null hypothesis in favor of the claim

And the best conclusion for this case would be:

b)The p-value is 0.008, indicating sufficient evidence for his claim.

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3 years ago
Can someone please answer i will mark brainliest
Dmitrij [34]
A) 2007
b) 120
c) the donations are decreasing as years increase
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2 years ago
Read 2 more answers
The expression in the figure below represent the measures of two angle.Find the value of x . f || g . The diagram is not to scal
Andrej [43]
I hope this helps you




2x and 8x+40 complementary angles

their sum is 180



2x+8x+40=180


10x=140


x=14
5 0
2 years ago
52.5% rounded to 1 decimal point
Law Incorporation [45]
52.5 already has 1 decimal point.. no more rounding needed.
7 0
2 years ago
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