Answer:
The probability that at most 1 car will require major engine repair next year is P=0.3392.
Step-by-step explanation:
This can be modeled as a binomial random variable, with n=22 and p=0.1.
The probability that exavtly k cars will require major engine repair next year is:
Then, the probability that at most 1 car will require major engine repair next year is:
Answer:69
Step-by-step explanation:
Answer:
so the value of x is 8.3333≈8.3
Step-by-step explanation:
3x:10=5:2
by cross-multiplication
3x×2=5×10
6x=50
6x/6=50/6
x=8.33
i hope this will help you :)
Here it is listed from greatest to least:
56.32, 56.321, 56.2