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3 years ago

Graph the following equation Y=3/4x-2

1 answer:

4 0

Your first point is your y-intercept, which is -2. That means you plot a point at (0,-2).

From that point rise 3 and run (to the right) 4. Plot your second point there.

Connect the two points.

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The sum of three consecutive odd numbers is one hundred fifty-nine

xeze [42]

First remember that sum means to add. now think about the equation. we need to find 3 numbers that equal 159 when added together. And they are all consecutive odd numbers. so let's call the first number X. the second number would be X+2 since we have to jump over 1 even number. The third number would be X+4 since we have to jump over 2 even numbers. so now an equation to represent this would be X+(X+2)+(X+4)=159. Add like terms, and remember order of operations. if you need help getting the answers leave me a comment.

8 0

3 years ago

The equation 2.2x − 4.4 = 1.8x can be transformed to form which of the following expressions?

Anna35 [415]

The answer to this mathematical question would be "0.4x = 4.4". I simply subtracted 1.8x to both sides of the equation (following the subtraction property of equations) and then added 4.4 to both sides of the equation (following the addition property of equations). Thus, we arrive to the answer, 0.4x = 4.4.

6 0

3 years ago

Read 2 more answers

If 6 beads weigh 48 grams, how many beads weigh 72 grams?

allochka39001 [22]

Nine.
48 divided by 6 is 8, which means that each bead weighs 8 grams.
72 divided by 8 is nine.

4 0

3 years ago

Read 2 more answers

A manufacturer uses production method to produce steel rods. A random sample of 17 steel rods resulted in lengths with a standar

Arisa [49]

Answer:

$\chi^2 =\frac{17-1}{12.15} 22.09 =15.87$

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates $\alpha/2 =0.05$ of the area on each tail and we got:

$\chi^2_{crit}= 7.962$

$\chi^2_{crit}=26.296$

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is NOT significantly different from 3.5 cm

Confidence level method

We can find the p value like this

$p_v =2*P(\chi^2 >15.87)=0.92$

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is NOT significantly different from 3.5 cm

Step-by-step explanation:

Data provided

$n=17$ represent the sample selected

$\alpha=0.1$ represent the significance

$s^2 =4.7^2 =22.09$ represent the sample variance

$\sigma^2_0 =3.5^2 =12.15$ represent the value to check

Null and alternative hypothesis

We want to verify if the new production method has lengths with a standard deviation different from 3.5 cm, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 = 12.15$

Alternative hypothesis: $\sigma^2 \neq 12.15$

The statistic for this case is given by:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

The degrees of freedom are:

$df =n-1= 17-1=16$

$\chi^2 =\frac{17-1}{12.15} 22.09 =15.87$

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates $\alpha/2 =0.05$ of the area on each tail and we got:

$\chi^2_{crit}= 7.962$

$\chi^2_{crit}=26.296$

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is significantly different from 3.5 cm

Confidence level method

We can find the p value like this

$p_v =2*P(\chi^2 >15.87)=0.92$

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is significantly different from 3.5 cm

7 0

3 years ago

SHOW WORK

mote1985 [20]

1). The answer is 86. .29n =24.94
In order to obtain this you need to divide both sides by .29

2) The answer is 25%
35/140 x 100% =25%

3) The answer is $70
So if 100% of 40 is 40 and 75% of 40 is 30 than you need to add 40 + 30 which equals 70.

Hope this helps :)

4 0

3 years ago