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2 years ago

(02.02 MC)

Mathematics

2 answers:

Crank2 years ago

8 0

Answer: 2 over 7

Step-by-step explanation:

2/(2+5) = 2/7

cricket20 [7]2 years ago

6 0

Answer:

2/5 or two over five

Step-by-step explanation:

2:5

Divide each by 5

2/5 : 1

2/5 * 1

2/5

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Read 2 more answers

I just need these questions answered, there is no requirement for any explanation! If anybody could assist, that would be great!

koban [17]

Answer:

See explanation

Step-by-step explanation:

Q9. Statement Reason

1) $\angle ABD \cong \angle CBD$ Given

2) $\overline{AB}\cong \overline{CB}$ Given

3) $\overline{BD}\cong \overline {BD}$ Reflexive property

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5) $\angle A\cong \angle C$ Corresponding parts of congruent triangles are congruent.

Q8. Statement Reason

1) $\overline{AD}\parallel \overline{BC}$ Given

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3) $\angle AED\cong \angle CEB$ Vertical angles theorem

4) $\overline{AE}\cong \overline{EC}$ Given

5) $\triangle AED\cong \triangle CEB$ ASA postulate

Q7.

1) $\overline{BC}\cong \overline {EF}$ - Given

$\angle CBA\cong \angle FED$ - Given

Pairs of needed sides or pair of needed angles:

$\overline{AB}\cong \overline{DE}$

The postulate or theorem that can be used to prove the triangles are congruent:

SAS postulate

2) $\overline{BC}\cong \overline {EF}$ - Given

$\overline{AC}\cong \overline {DF}$ - Given

Pairs of needed sides or pair of needed angles:

$\overline{AB}\cong \overline{DE}$

The postulate or theorem that can be used to prove the triangles are congruent:

SSS postulate

3) $\overline{BC}\cong \overline {EF}$ - Given

$\angle CBA\cong \angle FED$ - Given

Pairs of needed sides or pair of needed angles:

$\angle ACB\cong \angle DFE$

The postulate or theorem that can be used to prove the triangles are congruent:

ASA postulate

4) $\overline{BC}\cong \overline {EF}$ - Given

$\angle CBA\cong \angle FED$ - Given

Pairs of needed sides or pair of needed angles:

$\angle CAB\cong \angle FDE$

The postulate or theorem that can be used to prove the triangles are congruent:

AAS postulate

Q10. Statement Reason

1) $\angle MCI\cong \angle AIC$ Given

2) $\overline{MC}\cong \overline{AI}$ Given

3) $\overline{CI}\cong \overline{CI}$ Reflexive property

4) $\triangle MCI\cong \triangle AIC$ SAS postulate

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3 years ago

Find an equation for the line that passes through the points (4,3) and (-6,5)

mixer [17]

Answer:

y = -1/5x + 19/5 or

x + 5y = 19.

Step-by-step explanation:

The slope of the line (m) = (5-3) / (-6-4)

= -1/5.

Using the point-slope form of the equation of a line:

y - y1 = m(x - x1) m = -1/5. x1 = 4 and y1 = 3 , so:

y - 3 = -1/5(x - 4)

y - 3 = -1/5x + 4/5

y = -1/5x + 19/5 which is the equation in slope-intercept form.

Converting to standard form ( multiplying by 5):

5y = -x + 19

x + 5y = 19.

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3 years ago