Answer:
x = 7/5 or x = (-7)/5
Step-by-step explanation:
Solve for x over the real numbers:
49 - 25 x^2 = 0
Multiply both sides by -1:
25 x^2 - 49 = 0
x = (0 ± sqrt(0^2 - 4×25 (-49)))/(2×25) = ( ± sqrt(4900))/50:
x = sqrt(4900)/50 or x = (-sqrt(4900))/50
sqrt(4900) = sqrt(4×25×49) = sqrt(2^2×5^2×7^2) = 2×5×7 = 70:
x = 70/50 or x = (-70)/50
70/50 = 7/5:
x = 7/5 or x = (-70)/50
(-70)/50 = -7/5:
Answer:x = 7/5 or x = (-7)/5
Answer:
9/5 < m < 9/4
Step-by-step explanation:
The conditions are:
- The line passes through (9,4)
- The slope (m) is greater than its y-intercept
If we take a point like (-1,0)
Slope (m) = change in y ÷ change in x =
= 9/5
This point satisfies the conditions above since;
- The line passes through points (9,0) and (-1,0)
- The x-intercept is negative i.e -1
- The y-intercept is 0 and the slope which equals 9/5 is greater than 0
From the choices given;
we can say that:
m > 9/5 and m < 9/4
And can be expressed as;
9/5 < m < 9/4
I think it would be C B and E for number 1 and for the second problem 78 one and 263 thousandths, the next is 782 tenths and 63 thousandths, and 78263 thousandths for the last one. Correct me if I am wrong.
Answer : C , (L'M')` has a slope of 1.75 and passes through point C
Polygon JKLM is dilated by a scale factor of 2.5 with point C as the center of dilation, resulting in the image J′K′L′M′.
Given : Point C lies on the line LM and the slope of LM is 1.75.
In dilation by scale factor , the size of the polygon will increase or decrease.
the slope will not change by dilation. The slope remains the same.
So the slope of L'M' is 1.75
The line (L'M') has a slope of 1.75 and passes through point C.
Don't see any options, but b+c would be traveling with the current, and b-c would be traveling against the current.