X+y+z = 132
x = 7+z
y = 3z
(7+z)+3z+z = 132
5z = 132-7
z = 125/5
z = 25 <=====
x = 7+z
x = 7 + 25
x = 39 <=====
y = 3z
y = 3 × 25
y = 75 <=====
hope it helps :)
Answer:
x= -2-√11. or. x= -2 + √11
Step-by-step explanation:
solving quadratic equation by completing the square
x^2+4x-7=0
x^2+4x=7
x^2+4x + (4/2)^2=7 + (4/2)^2 ( adding (1/2 coefficient of x)^2 on both sides
x^2+4x + 4=7 + 4
x^2+4x + 4=11. factorize(x^2+4x + 4) into (x + 2)^2
(x + 2)^2=11
√(x + 2)^2= + - √11
x + 2 = + - √11
there are two different solution .
x + 2 = -√11. or x + 2 = + √11.
x= -2-√11. or. x= -2 + √11.
Answer:
C - 1 / sin^2x
Step-by-step explanation:
as csc x = 1 / sin x
so, csc^2 x = 1 / sin^ 2x
Answer:
Step-by-step explanation:
Answer:
10
Step-by-step explanation:
your welcome...............
