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anygoal [31]
3 years ago
8

A basketball with a diameter of 9.5 in. is placed in a cubic box with sides 15 in. long. How many cubic inches of packing foam a

re needed to fill the rest of the box? Round to the nearest tenth.
Mathematics
1 answer:
Doss [256]3 years ago
4 0

Answer:

The volume of foam needed to fill the box is approximately 2926.1 cubic inches.

Step-by-step explanation:

To calculate the amount of foaming that is needed to fill the rest of the box we first need to calculate the volume of the box and the volume of the ball. Since the box is cubic it's volume is given by the formula below, while the formula for the basketball, a sphere, is also shown.

Vcube = a³

Vsphere = (4*pi*r³)/3

Where a is the side of the box and r is the radius of the box. The radius is half of the diameter. Applying the data from the problem to the expressions, we have:

Vcube = 15³ = 3375 cubic inches

Vsphere = (4*pi*(9.5/2)³)/3 = 448.921

The volume of foam there is needed to complete the box is the subtraction between the two volumes above:

Vfoam = Vcube - Vsphere = 3375 - 448.921 = 2926.079 cubic inches

The volume of foam needed to fill the box is approximately 2926.1 cubic inches.

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Answer:

36.7

Step-by-step explanation:

its right :)

3 0
3 years ago
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If f(x) = 2(3^x) + 1, what is the value of f(2)?<br> (1) 13<br> (3) 37<br> (2) 19<br> (4) 54
DanielleElmas [232]
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What is the next fraction in each of the following patterns?1/40,4/40,9/40,16/40,25/40...?
tresset_1 [31]
Let
a1=1/40
a2=4/40
a3=9/40
a4=16/40
a5=25/40
a6=?

we know that
a2-a1=4/40-1/40----> 3/40
a3-a2=9/40-4/40-----> 5/40
a4-a3=16/40-9/40----> 7/40
a5-a4=25/40-16/40---> 9/40

the difference is
3/40,5/40,7/40.9/40,....
3/40+[2/40]---> 5/40
5/40+[2/40]---> 7/40
7/40+[2/40]---> 9/40

the next will be
9/40+[2/40]-----> 11/40
so
the next term is 25/40+[11/40]------> 36/40

the answer is
36/40
5 0
3 years ago
What is the slope of the line
Papessa [141]

Answer:

2/3

Step-by-step explanation:

rise over run is 2 over 3, and it is positive because the y increases as the x increases!

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2 years ago
A cylinder has a radius of 4 inches and a high of 10.5 inches what is the approximate volume of the cylinder
olga55 [171]

Answer:

V ≈ 527.79

Step-by-step explanation:

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therefore

V = π * 4 * 2 * 10.5

V = π * 8 * 10.5

V ≈ 527.79

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