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anygoal [31]
3 years ago
8

A basketball with a diameter of 9.5 in. is placed in a cubic box with sides 15 in. long. How many cubic inches of packing foam a

re needed to fill the rest of the box? Round to the nearest tenth.
Mathematics
1 answer:
Doss [256]3 years ago
4 0

Answer:

The volume of foam needed to fill the box is approximately 2926.1 cubic inches.

Step-by-step explanation:

To calculate the amount of foaming that is needed to fill the rest of the box we first need to calculate the volume of the box and the volume of the ball. Since the box is cubic it's volume is given by the formula below, while the formula for the basketball, a sphere, is also shown.

Vcube = a³

Vsphere = (4*pi*r³)/3

Where a is the side of the box and r is the radius of the box. The radius is half of the diameter. Applying the data from the problem to the expressions, we have:

Vcube = 15³ = 3375 cubic inches

Vsphere = (4*pi*(9.5/2)³)/3 = 448.921

The volume of foam there is needed to complete the box is the subtraction between the two volumes above:

Vfoam = Vcube - Vsphere = 3375 - 448.921 = 2926.079 cubic inches

The volume of foam needed to fill the box is approximately 2926.1 cubic inches.

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What is a quadratic polynomial function with zeros 3 and -3?​
Lemur [1.5K]

Answer:

f(x) = x² - 9

Step-by-step explanation:

Given x = a is a zero of the polynomial f(x) then (x - a) is a factor

Given zeros are x = 3 and x = - 3, then corresponding factors are

(x - 3) and (x - (- 3) ), that is

(x - 3) and (x + 3)

The function is then the product of the factors, that is

f(x) = (x - 3)(x + 3) ← expand using FOIL

f(x) = x² - 9

8 0
3 years ago
Please help! I’m on a timer :/
weqwewe [10]

If you want to find out how Addision paid each month, you have to have 36, then divide 36 by 12, and the answer will give you 3. So Addison paid $3 every month.

Hope this Helped

Nate

4 0
3 years ago
Read 2 more answers
1) Use Newton's method with the specified initial approximation x1 to find x3, the third approximation to the root of the given
neonofarm [45]

Answer:

Check below, please

Step-by-step explanation:

Hello!

1) In the Newton Method, we'll stop our approximations till the value gets repeated. Like this

x_{1}=2\\x_{2}=2-\frac{f(2)}{f'(2)}=2.5\\x_{3}=2.5-\frac{f(2.5)}{f'(2.5)}\approx 2.4166\\x_{4}=2.4166-\frac{f(2.4166)}{f'(2.4166)}\approx 2.41421\\x_{5}=2.41421-\frac{f(2.41421)}{f'(2.41421)}\approx \mathbf{2.41421}

2)  Looking at the graph, let's pick -1.2 and 3.2 as our approximations since it is a quadratic function. Passing through theses points -1.2 and 3.2 there are tangent lines that can be traced, which are the starting point to get to the roots.

We can rewrite it as: x^2-2x-4=0

x_{1}=-1.1\\x_{2}=-1.1-\frac{f(-1.1)}{f'(-1.1)}=-1.24047\\x_{3}=-1.24047-\frac{f(1.24047)}{f'(1.24047)}\approx -1.23607\\x_{4}=-1.23607-\frac{f(-1.23607)}{f'(-1.23607)}\approx -1.23606\\x_{5}=-1.23606-\frac{f(-1.23606)}{f'(-1.23606)}\approx \mathbf{-1.23606}

As for

x_{1}=3.2\\x_{2}=3.2-\frac{f(3.2)}{f'(3.2)}=3.23636\\x_{3}=3.23636-\frac{f(3.23636)}{f'(3.23636)}\approx 3.23606\\x_{4}=3.23606-\frac{f(3.23606)}{f'(3.23606)}\approx \mathbf{3.23606}\\

3) Rewriting and calculating its derivative. Remember to do it, in radians.

5\cos(x)-x-1=0 \:and f'(x)=-5\sin(x)-1

x_{1}=1\\x_{2}=1-\frac{f(1)}{f'(1)}=1.13471\\x_{3}=1.13471-\frac{f(1.13471)}{f'(1.13471)}\approx 1.13060\\x_{4}=1.13060-\frac{f(1.13060)}{f'(1.13060)}\approx 1.13059\\x_{5}= 1.13059-\frac{f( 1.13059)}{f'( 1.13059)}\approx \mathbf{ 1.13059}

For the second root, let's try -1.5

x_{1}=-1.5\\x_{2}=-1.5-\frac{f(-1.5)}{f'(-1.5)}=-1.71409\\x_{3}=-1.71409-\frac{f(-1.71409)}{f'(-1.71409)}\approx -1.71410\\x_{4}=-1.71410-\frac{f(-1.71410)}{f'(-1.71410)}\approx \mathbf{-1.71410}\\

For x=-3.9, last root.

x_{1}=-3.9\\x_{2}=-3.9-\frac{f(-3.9)}{f'(-3.9)}=-4.06438\\x_{3}=-4.06438-\frac{f(-4.06438)}{f'(-4.06438)}\approx -4.05507\\x_{4}=-4.05507-\frac{f(-4.05507)}{f'(-4.05507)}\approx \mathbf{-4.05507}\\

5) In this case, let's make a little adjustment on the Newton formula to find critical numbers. Remember their relation with 1st and 2nd derivatives.

x_{n+1}=x_{n}-\frac{f'(n)}{f''(n)}

f(x)=x^6-x^4+3x^3-2x

\mathbf{f'(x)=6x^5-4x^3+9x^2-2}

\mathbf{f''(x)=30x^4-12x^2+18x}

For -1.2

x_{1}=-1.2\\x_{2}=-1.2-\frac{f'(-1.2)}{f''(-1.2)}=-1.32611\\x_{3}=-1.32611-\frac{f'(-1.32611)}{f''(-1.32611)}\approx -1.29575\\x_{4}=-1.29575-\frac{f'(-1.29575)}{f''(-4.05507)}\approx -1.29325\\x_{5}= -1.29325-\frac{f'( -1.29325)}{f''( -1.29325)}\approx  -1.29322\\x_{6}= -1.29322-\frac{f'( -1.29322)}{f''( -1.29322)}\approx  \mathbf{-1.29322}\\

For x=0.4

x_{1}=0.4\\x_{2}=0.4\frac{f'(0.4)}{f''(0.4)}=0.52476\\x_{3}=0.52476-\frac{f'(0.52476)}{f''(0.52476)}\approx 0.50823\\x_{4}=0.50823-\frac{f'(0.50823)}{f''(0.50823)}\approx 0.50785\\x_{5}= 0.50785-\frac{f'(0.50785)}{f''(0.50785)}\approx  \mathbf{0.50785}\\

and for x=-0.4

x_{1}=-0.4\\x_{2}=-0.4\frac{f'(-0.4)}{f''(-0.4)}=-0.44375\\x_{3}=-0.44375-\frac{f'(-0.44375)}{f''(-0.44375)}\approx -0.44173\\x_{4}=-0.44173-\frac{f'(-0.44173)}{f''(-0.44173)}\approx \mathbf{-0.44173}\\

These roots (in bold) are the critical numbers

3 0
3 years ago
A pharmaceutical company decided to manufacture new food supplement pills. It will need to add some vitamins to the mix. It deci
WINSTONCH [101]

Answer:

Minimize:    Cost = 40X+35Y

Subject to:  2X + 2Y ≥ 12

                   5X + 3Y ≥ 15

Step-by-step explanation:

To formulate a linear programming model we need to identify the variables of decision, the objective functions and the constraints.

So, the variables of decision are the quantity of every vitamin mix and we are going to call:

X: The quantity of vitamin mix 1

Y: The quantity of vitamin mix 2

Our objective function is going to be minimize the cost of the both mixes, so, the objective function is:

Minimize Cost = 40X + 35Y

Because vitamin mix 1 cost $40 and vitamin mix 2 cost $35

Finally, the constraints are defined by the following sentence: both mixes have to contain at least 12 units of vitamin B and 15 of vitamin C. Ot means that we have a constraint for vitamin B and a constraint for vitamin C.

Then if Vitamin mix 1 contains 2 units of vitamin B and vitamin mix 2 contain 2 units of vitamin B, the constraint associated to vitamin B is:

2X + 2Y ≥ 12

And, if Vitamin mix 1 contains 5 units of vitamin C and vitamin mix 2 contain 3 units of vitamin C, The constraint associated to vitamin C is:

5X + 3Y ≥ 15

So, the linear programing model is:

Minimize:    Cost = 40X+35Y

Subject to:  2X + 2Y ≥ 12

                   5X + 3Y ≥ 15

7 0
3 years ago
You spin the spinner, flip a coin, then spin the spinner again. Find the probability of the compound event. Write your answer as
Paraphin [41]

Answer:

The probability of not spinning a 5, flipping heads, then spinning a 1 is 0.08

Step-by-step explanation:

I may assume the spin contains 5 numbers ( plz change and recalculate if the no. of numbers is different)

P(not spinning a 5) = 4/5

P(flipping head) = 1/2

P(spinning 1) = 1/5

P(not spinning a 5, flipping heads, then spinning a 1)= 4/5   *    1/2   *   1/5 = 0.08 = 0.1

5 0
3 years ago
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