Answer:
4) 40 Square inches
Step-by-step explanation:
You do 2 x 4 then divide by 2. after that you multiply by 4. Then you add the square which is 2 x 2
Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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<span>THE GIVEN QUESTION;
7x -3(4x-8) < 6x +12 - 9x
THE GIVEN INTERVAL OF X IS FROM [4,8] SO THE VALUE OF X ={4,5,6,7,8}
THE GIVEN QUESTION CAN BE EVALUATED TO
7x - 12x+ 24 < 12 - 3x
-5x + 24 < 12 - 3x //USING BODMAS RULE
NOW SUBSTITUTING THE VALUE OF X:
1) X=4 SOL: 4<0
2) X=5 SOL: -1<-3
3) X=6 SOL: -6<-6
4) X=7 SOL: -11<-9
5) X=8 SOL: -16<-12
HENCE THE VALUE OF X=7,8 SATISFY THE GIVEN INEQUALITY</span>
Answer: 2/3, 1/2, 5/8,7/11
Step-by-step explanation: usually the smaller your denominator is the larger your fraction. You also have to look at the numerator and somewhat visualize what it would look like. Such as 2/3 is larger than 1/2 because 1/2 of 3 is 1.5 so since 2 is larger than 1.5 you can say 2/3 is larger
Hope this helps
I think it is ae if i get it wrong sorry goodluck
