Answer:
Step-by-step explanation:
let the speed of one plane=x
speed of other plane=x+80
time=4 hrs
then 4x+4(x+80)=3800
4x+4x+320=3800
8x=3800-320
or 8x=3480
x=435
speed of one plane=435 m/h
speed of other plane=435+80=515 m/h
2.
Let he walks x hrs
then he take a taxi for 2-x hrs
4x+(2-x)50=31
4x+100-50x=31
-46x=-69
so he walks 3/2 hrs=1.5 hrs
travels by taxi=2-1.5=0.5 hrs
distance traveled by taxi=0.5×50=25 miles
Answer:
(c) Probability that a failure is due to loose keys = 0.2376
(d) Probability that a failure is due to improperly connected or poorly welded wires = 0.078
Step-by-step explanation:
The Whole probability scenario is given for Computer Keyboard failures.
(a) Let F be the event of failure due to faulty electrical connects, P(F) = 0.12
M be the event of failure due to mechanical defects, P(M) = 0.88
LK be the event of mechanical defect due to loose keys, P(LK/M) = 0.27
IA be the event of mechanical defect due to improper assembly, P(IA/M) =0.73
DW be the event of electrical connects due to defective wires,P(DW/F) = 0.35
IC be the event of electrical connects due to improper connections,
P(IC/F) = 0.13 .
PWW be the event of electrical connects due to poorly welded wires,
P(PWW/F) = 0.52
(b) <u> </u><u>Keyboard failures</u>
<h2> / \</h2><u> </u><u> Faulty electrical connects </u> <u>Mechanical Defects </u>
P(F) = 0.12 P(M) = 0.88
<h2> / | \ / \</h2><u><em>Defective wires</em></u> <u><em>Improper</em></u> <u><em>Poorly</em></u> <u><em>Loose Keys</em></u> <u><em>Improper</em></u><em> </em>
P(DW/F)=0.35 <u><em>Connections</em></u> <u><em>Welded wires</em></u> P(LK/M)=0.27 <em> </em><u><em>Assembly</em></u>
P(IC/F)=0.13 P(PWW/F)=0.52 P(IA/M)=0.73
This is the required tree diagram.
(c) Probability that a failure is due to loose keys is given by:
P(LK) =P(LK/M) * P(M) {This means mechanical failure is due to loose
keys}
P(LK) = 0.27 * 0.88 = 0.2376 .
(d) Probability that a failure is due to improperly connected or poorly welded
wires is given by P(IC PWW) ;
P(IC PWW) = P(IC) + P(PWW) - P(IC
PWW) { Here P(IC
PWW) = 0 }
P(IC) = P(IC/F) * P(F) = 0.13 * 0.12 = 0.0156
P(PWW) = P(PWW/F) * P(F) = 0.52 * 0.13 = 0.0676
Therefore, P(IC PWW) = 0.0156 + 0.0676 - 0 = 0.078 .