Answer:F=7
Step-by-step explanation:
<h3>
Answer: Choice C</h3>
P = 11/40 + 1/4 - 1/20
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Explanation:
The formula we use is
P(A or B) = P(A) + P(B) - P(A and B)
In this case,
- P(A) = 22/80 = 11/40 = probability of picking someone from consumer education
- P(B) = 20/80 = 1/4 = probability of picking someone taking French
- P(A and B) = 4/80 = 1/20 = probability of picking someone taking both classes
So,
P(A or B) = P(A) + P(B) - P(A and B)
P(A or B) = 11/40 + 1/4 - 1/20
which is why choice C is the answer
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Note: P(A and B) = 1/20 which is nonzero, so events A and B are not mutually exclusive.
Answer:
The answer is false
Step-by-step explanation:
In a sample above 30 obs like this the confidence interval is defined as
X+- t* (s/sqrt(n)) where X is the mean t the tvalue for a given confidence level, n the size of sample and s standar deviation.
To find de appropiate value of t we must see the T table where rows are degrees of freedom and columns significance level
The significance is obtained:
significance = 1 - confidence level = 1 - 0.9 = 0.10
Degrees of freedom (df) for the inteval are
df = n - 1 = 18 - 1 = 17
So we must look for the value of a t with 17 values and significance of 0.10 which in t table is 1.740 not 1.746 ( thats the t for 16 df)
Solve for y
minus 10x from both sides
5y<-10x+15
divide both sides by 5
y<-2x+3
