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Anna007 [38]
3 years ago
6

8. Two alarms ring simultaneously

Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
7 0
They will meet for a third time at 6am because 20 is one third of 60. So when the first alarm rings three times the second one will also ring. Then since the question is asking when the alarms ring for the third time together you ha e to add three hours to 3am because they always meet on the hour. Hope this helps!
Anestetic [448]3 years ago
4 0
3:20 then 3:40 then 4:00 for both
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In psychology, there is a particular Mental Development Index (MDI) used in the study of infants. The scores on the MDI have app
ivann1987 [24]

Answer:

0.1587

Step-by-step explanation:

Here, mean=μ=100 and standard deviation=σ=16.

We have to find  P(average MDI scores of 64 children > 102)=P(xbar>102).

n=64

μxbar=μ=100

σxbar=σ/√n=16/√64=16/8=2

P(xbar>102)=P((xbar-μxbar)/σxbar>(102-100)/2)

P(xbar>102)=P(z>1)

P(xbar>102)=P(0<z<∞)-P(0<z<1)

P(xbar>102)=0.5-0.3413

P(xbar>102)=0.1587

Thus, the probability that the average is greater than 102 is 15.87%

4 0
3 years ago
Two times the greater of two consecutive integers is 9 less than three times the lesser integer. What are the integers?
blondinia [14]
Let the two integers be x and x + 1, then
2(x + 1) + 9 = 3x
2x + 2 + 9 = 3x
3x - 2x = 11
x = 11

Therefore, the integers are 11 and 12.

6 0
3 years ago
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aalyn [17]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
Solve the equation 4s2+32s=60 by completing the square
lord [1]

Answer:

s = -4 ± √31

Step-by-step explanation:

Given 4s^{2} + 32s = 60

divide by 4 throughout

s^{2}  + 8s = 15\\s^{2} + 8s + (\frac{8}{2}) ^{2}  = 15 + (\frac{8}{2}) ^{2}

 (s + 4)^{2}  = 31\\s + 4 = \sqrt{31}

s = -4 ± √31

7 0
3 years ago
What are the solutions of the equation x4 + 6x2 + 5 = 0? Use u substitution to solve.
klio [65]

Answer:

x = i and x = i\sqrt{5}

Step-by-step explanation:

Given

x^{4} + 6x² + 5 = 0

Using the substitution u = x², then

u² + 6u + 5 = 0 ← in standard form

(u + 1)(u + 5) = 0 ← in factored form

Equate each factor to zero and solve for u

u + 1 = 0 ⇒ u = - 1

u + 5 = 0 ⇒ u = - 5

Convert solutions back into terms of x

x² = - 1 ⇒ x = \sqrt{-1} = i

x² = - 5 ⇒ x = \sqrt{-5} = i\sqrt{5}

4 0
3 years ago
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