Answer:
0.1587
Step-by-step explanation:
Here, mean=μ=100 and standard deviation=σ=16.
We have to find  P(average MDI scores of 64 children > 102)=P(xbar>102).
n=64
μxbar=μ=100
σxbar=σ/√n=16/√64=16/8=2
P(xbar>102)=P((xbar-μxbar)/σxbar>(102-100)/2)
P(xbar>102)=P(z>1)
P(xbar>102)=P(0<z<∞)-P(0<z<1)
P(xbar>102)=0.5-0.3413
P(xbar>102)=0.1587
Thus, the probability that the average is greater than 102 is 15.87%
 
        
             
        
        
        
Let the two integers be x and x + 1, then
2(x + 1) + 9 = 3x
2x + 2 + 9 = 3x
3x - 2x = 11
x = 11
Therefore, the integers are 11 and 12.
        
             
        
        
        
Answer:
what are you telling Id understand
Step-by-step explanation:
became
 
        
             
        
        
        
Answer:
s = -4 ± √31
Step-by-step explanation:
Given 4 + 32s = 60
 + 32s = 60
divide by 4 throughout
 
  
s = -4 ± √31
 
        
             
        
        
        
Answer:
x = i and x = i
Step-by-step explanation:
Given
 + 6x² + 5 = 0
 + 6x² + 5 = 0
Using the substitution u = x², then
u² + 6u + 5 = 0 ← in standard form
(u + 1)(u + 5) = 0 ← in factored form
Equate each factor to zero and solve for u
u + 1 = 0 ⇒ u = - 1
u + 5 = 0 ⇒ u = - 5
Convert solutions back into terms of x
x² = - 1 ⇒ x =  = i
 = i
x² = - 5 ⇒ x =  = i
 = i